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3 years ago

How do you do this? Help me

Mathematics

2 answers:

guajiro [1.7K]3 years ago

6 0

The answer is nine !! hope it is right

dangina [55]3 years ago

4 0

Answer:

D. 9

Step-by-step explanation:

You'll get it right, just trust me.

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a set v is given, together with definitions of addition and scalar multiplication. determine which properties of a vector space

agasfer [191]

The properties of a vector space are satisfied Properties 1,2, 5(a) and 5(c) are satisfied, the relaxation of the homes aren't legitimate are if $v = x ^ 2 1× v=1^ ×x ^ 2 = 1 #V$

Property three does now no longer follow: Suppose that Property three is legitimate, shall we name $v = a * x ^ 2 +bx +c$ the neuter of V. Since v is the neuter, then O have to be constant with the aid of using the neuted, consequently $0 = O + v = (O x ^ 2 + Ox + O) + (a × x ^ 2 + bx + c) = c × x ^ 2 + b ^ 2 + a$

= 0 If O is the neuter, then it ought to restore x², but $0+ x² = (0x²+0x+zero) + (x²+0x+zero) = 1.$ This is a contradiction due to the fact x² isn't 1. We finish that V doesnt have a neuter vector. This additionally method that belongings four would not observe either. A set with out 0 cant

have additive inverse

$Let r= v ×2x ^ 2 + v × 1x +v0 , w= w ×2x ^ 2 + w × 1x +w0 . We have that\\v+w= (vO + wO) ^ x^ 2 +(vl^ × wl)^ x+ ( v 2^ × w2)• w+v= (wO + vO) ^x^ 2 +(wl^ × vl)x+ ( w 2^ ×v2)$

Since the sum of actual numbers is commutative, we finish that v + w = w + v Therefore, belongings 5(a) is valid.

Property 5(b) isn't valid: we are able to introduce

a counter example. we could use z = 1 then $v = x ^ 2 w = x ^ 2 + 1\\(v + w) + z = (x ^ 2 + 2) + 1 = 3x ^ 2 + 1$

v + (w + z) = x ^ 2 + (2x ^ 2 + 1) = x ^ 2 + 3

Since 3x ^ 2 +1 ne x^ 2 +3. then the associativity rule doesnt hold.

$(1+2)^ * (x^ 2 +x)=3^ * (x ^ 2 + x) = 3x + 3\\1^ × (x^ 2 +x)+2^ × (x ^ 2 + x) = (x + 1) + (2x + 2) = 3x ^ 2 + x ( ne 3x + 3 )\\(1^ ×2)^ ×(x^ 2 +x)=2^ × (x ^ 2 + x) = 2x + 2\\1^ × (2^ × (x ^ 2 + x) )=1^ × (2x+2)=2x^ 2 +2x( ne2x+2)$

Property f doesnt observe because of the switch of variables. for instance, if v = x ^ 2 1 × v=1^ × x ^ 2 = 1 #V

Properties 1,2, 5(a) and 5(c) are satisfied, the relaxation of the homes arent legitimate.

Step-with the aid of using-step explanation:

Note that each sum and scalar multiplication entails in replacing the order from that most important coefficient with the impartial time period earlier than doing the same old sum/scalar multiplication.

Property three does now no longer follow: Suppose that Property three is legitimate, shall we name v = a × x ^ 2 +bx +c the neuter of V. Since v is the neuter, then O have to be constant with the aid of using the neuted, consequently $0 = O + v = (O × x ^ 2 + Ox + O) + (a × x ^ 2 + bx + c) = c × x ^ 2 + b ^ 2 + a$

= zero If O is the neuter, then it ought to restore x², but zero $+ x² = (0x²+0x+zero) + (x²+0x+zero) = 1.$ This is a contradiction due to the fact x² isn't 1. We finish that V doesnt have a neuter vector. This additionally method that belongings four would not observe either. A set with out 0 cant have additive inverse

Let $r= v × 2x ^ 2 + v × 1x +v0 , w= w2x ^ 2 + w × 1x +w0 . \\We have thatv+w= (vO + wO) ^ x^ 2 +(vl^ wl)^x+ ( v 2^ w2)w+v= (wO + vO) ^ x^ 2 +(wl^ vl)x+ ( w 2^v2)$

Since the sum of actual numbers is commutative, we finish that v + w = w + v Therefore, belongings 5(a) is valid.

Property 5(b) isn't valid: we are able to introduce

a counter example. we could use $z = 1 then v = x ^ 2 w = x ^ 2 + 1(v + w) + z = (x ^ 2 + 2) + 1 = 3x ^ 2 + 1v + (w + z) = x ^ 2 + (2x ^ 2 + 1) = x ^ 2 + 3\\Since 3x ^ 2 +1 ne x^ 2 +3.$ then the associativity rule doesnt hold.

Note that each expressions are same because of the distributive rule of actual numbers. Also, you could be aware that his assets holds due to the fact in each instances we 'switch variables twice.

$· (1+2)^ * (x^ 2 +x)=3^ * (x ^ 2 + x) = 3x + 31^ * (x^ 2 +x)+2^ * (x ^ 2 + x) = (x + 1) + (2x + 2) = 3x ^ 2 + x ( ne 3x + 3 )(1^ * 2)^ * (x^ 2 +x)=2^ * (x ^ 2 + x) = 2x + 21^ * (2^ * (x ^ 2 + x) )=1^ ×* (2x+2)=2x^ 2 +2x( ne2x+2)$

Read more about polynomials :

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8 0

1 year ago

The range is the set of?

rosijanka [135]

Answer:

I think you forgot to attach the file...

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

How do you multiply and divide decimals ?

valina [46]

Multiplying Decimals

If you already know how to multiply, then multiplying decimals will be easy, there is just one extra step you need to take.
First, you multiply the numbers just like normal, as if the decimal point wasn't there.
Next, you need to add in the decimal point to the answer. This is the only tricky part. You add up the decimal places there are in the numbers you multiplied. Then you put that many decimal places in the answer.
Let's try some examples:

1) 4.22 x 3.1 = ?

If you first just multiply 422 x 31 you get

422
x 31
13082

Now, there are 2 decimal places in 4.22 and 1 decimal place in 3.1. This is a total of 3 decimal places. We then put three decimal places in 13082 and we finally get the answer:

13.082

1) 4.220 x 3.10 = ?

To show how the decimal part works, we'll solve the same problem again, but this time we will add a zero to the right of each number we multiply. This doesn't change the value of the numbers, so it shouldn't change the answer we get.

First we multiply without worrying about the decimals:

4220
x 310
1308200

Now, we count the total amount of decimals. There are 5 total decimals places this time. If we count over 5 decimal places from the end of 1308200 we get the same answer:

13.08200

Note: the extra zeros to the right of the decimal point do not change the value of the number.

Dividing Decimals

When you are dividing a number with a decimal point by a whole number, dividing decimals is pretty simple.
Divide the number as you normally would, using long division.
Bring the decimal point directly up from the dividend.
Example:

9.24 ÷ 7 = ?

If both divisor and dividend are decimals:

If the divisor is a decimal number rather than a whole number, then you need to take an extra step. In this step you convert the divisor from a decimal number to a whole number. You do this by moving the decimal point to the right in the divisor until there are no more numbers other than zero to the right of the decimal point. Then you move the decimal point to the right the same number of places in the dividend.

Example of moving the decimal point for division:

9.24 ÷ 7.008

You want the divisor 7.008 to be a whole number, so you need to move the decimal point 3 places to the right:

7008

Now you need to move the decimal point for the dividend 3 places to the right:

9240

In this case you have to add a zero to move it 3 places.

Now you divide 9240 by 7008 to get the answer:

Example:

0.64 ÷ 3.2 = ?

First move the decimal points so the divisor is a whole number:

6.4 ÷ 32 = ?

Important things to remember:
Move the decimal point directly up in your long division.
Always move the decimal points on BOTH to divisor and the dividend to where the divisor is a whole number.

hope this helps!! tell me if you need more assistance!!

7 0

3 years ago

Help please need help ASAP

Elanso [62]

Answer:

g phone the other questions please let me that he had an amazing time to Suna tha wo boli kya mama I have a doctor and square footage clip for more details on Friday November this year and square footage clip and square footage of rectangular shape or comments regarding the questions that may arise in touch as soon I have received a sum of Plassey and sahi h jo the questions I had to the best of Plassey the questions. Aladdin Nam to Suna he hoga

3 0

2 years ago

Solve the system of equation and choose the correct ordered pair.!2x-6y=8 5x-4y=31

kondor19780726 [428]

Answer:

The correct ordered pair is (7,1)

Step-by-step explanation:

The given system has equations:

$2x - 6y = 8....(1)$