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ale4655 [162]
3 years ago
8

Lorenzo recorded the favorite food of students in his class. According to the results of the survey, what percent of the student

s chose Hamburger?

Mathematics
1 answer:
nalin [4]3 years ago
4 0

Answer:

30%

Step-by-step explanation:

Before starting to solve this question we have to understand the following. 1% is equal to one hundredth of something whole, and can be write as \frac{1}{100} .

Now in order to solve this question we will first have to find a fraction that represent how much student out of the whole class choose hamburgers. We can easily find this fraction since the numerator of the fraction will be equal to the number of people that choose hamburgers and the denominator will be equal to the number of all students in the class. So we get......

\frac{12}{8 + 12 + 14+6} = \frac{12}{40}  = \frac{3}{10}

Now in order to find out what percentage will this fraction equal to we will have make a fraction with the same value but with a denominator being 100. To do that we will have to understand the following......

\frac{a}{b} = \frac{am}{bm} (m is any number except 0)

The main I idea of this rule is that if we multiply the numerator and the denominator by the same number (any number except 0) we will get a fraction with the same value but with a different denominator and numerator.

So in our case we we do the following.........

(multiply both numerator and the denominator by 10 and we get...)

\frac{3}{10} = \frac{(3)(10)}{(10)(10)} = \frac{30}{100}  

Now if we go back to what I said at the start of my explanation we will understand that another way of writing down \frac{30}{100} is 30%.

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Step-by-step explanation:

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Answer:

50~in

Step-by-step explanation:

perimter=AB+AM+BM

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50~in

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3 years ago
A chemical supply company currently has in stock 100 lb of a certain chemical, which it sells to customers in 5-lb batches. Let
rewona [7]

Complete Question:

A chemical supply company currently has in stock 100 lb of a certain chemical, which it sells to customers in 5-lb batches. Let X = the number of batches ordered by a randomly chosen customer, and suppose that X has the pmf shown in the table below. Compute E(X) and V(X).

Then compute the expected number of pounds left after the next customer’s order is shipped and the variance of the number of pounds left.

NOTE: The pmf is shown in the file attached

Answer:

Expected number of batches, E(X) = 2.0 batches

Variance of batches, V(X) = 0.8 batches²

Expected number of pounds left, E(Y) = 90 lb

Variance of pounds left, V(Y) = 20 lb²

Step-by-step explanation:

The company has 100 batches and it sells to customers in 5 lb batches. The number of pounds left after each customer is filled will be modeled by the mathematical formula: Y = 100 - 5X

The expected value of X, E(X) can be calculated using the formula:

E(X) = \sum x p(x)

E(X) = (1*0.3) + (2*0.5) + (3*0.1) + (4*0.1)

E(X) = 0.3 + 1 + 0.3 + 0.4

E(X) = 2.0

Expected number of batches, E(X) = 2.0 batches

The variance of X, V(X) can be calculated using the formula:

V(X) = E(X^2) - [E(X)]^2\\ E(X^2) = \sum x^2 p(x)\\  E(X^2) = (1^2 *0.3) + (2^2 * 0.5) + (3^2 * 0.1) + (4^2 * 0.1)\\  E(X^2) = 0.3 + 2 + 0.9 + 1.6\\ E(X^2) = 4.8\\V(X) = 4.8 - 2^2\\V(X) = 0.8

Variance of batches, V(X) = 0.8 batches²

Y = 100 - 5X

E(Y) = E(100 - 5X)

E(Y) = 100 - 5E(X)

E(Y) = 100 - 5(2)

E(Y) = 90 lb

Expected number of pounds left, E(Y) = 90 lb

Variance of the number of pounds left:

V(Y) = V(100 - 5X)

V(Y) = V(100) + V(-5X)

V(100) = 0

V(Y) = (-5)² V(X)

V(Y) = 25 * 0.8

V(Y) = 20

Variance of pounds left, V(Y) = 20 lb²

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