If he hits the target 95% of the time, then you could say that he has a probability of 0.95, or 95% of hitting the target. Let p = the probability of hitting the target or p = 0.95. So you are interested that he misses the target at least once - this could be thought of as not getting a perfect score. So to get a perfect score, it is 0.95 for each target -- 0.95^15 for 15 targets is 0.464. Thus to miss at least one target he needs to NOT have a perfect score -- 1 - 0.464 = 0.536, or 53.6% of happening. Enjoy
Rather than trial and error, you can do this with an equation.
x + x+1 + x+2 = 267 =>
3x+3 = 267
x = 264/3 = 88
So the numbers are 88+89+90. 90 is the largest number.
Divide 6 2/3 by 4 and you get an x value of 1.67 to double check the answer we can multiply 1 2/3 by 4 and we get 6 2/3
<h2>Problem 6:</h2><h2>a)</h2>
<h2>b)</h2>
<h2>c)</h2>
<h2 />
Answer:
113:348
Step-by-step explanation:
i got it wrong cause i only put 113 but it showed this is the answer
