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3 years ago

THESE ARE THE QUESTIONS WILL MARK BRAINLIEST 99 POINTS

Mathematics

2 answers:

telo118 [61]3 years ago

7 0

Answer:

Step-by-step explanation:

Arisa [49]3 years ago

4 0

1. You are given PR and RS, so simply add the two measurements to get PS.

28.2+30.7= 58.9

2. Subtract QV from QT to get TV.

78-56= 22

3. Again, Subtract QV from QT to get TV.

74-36= 38

4. Similar to question 1, add PR and RS to get PS.

40+53= 93

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Write 30/100 as a money amount and as a decimal in terms of a dollar

g100num [7]

Decimal: .3, money: $30/$100 Decimal is .3 because 30/100 is like saying 3/10 or .3/1

8 0

2 years ago

Read 2 more answers

Tony operates a skate rental company. He charges an equipment fee of $3 plus $6 per hour. Which equation represents this linear

slava [35]

Answer: A) y = 6x +3

Step-by-step explanation:

Let x represent the number of hours. $6 per hour can now be written as 6x.

Now, we must account for the $3 flat, fee and add it to 6x, getting 6x + 3

6 0

2 years ago

3^2 - 2x + 4 and g(x) = 5x^2 + 6x - 8 find f-g(x)

sveta [45]

Answer:

For the given functions f(x) and g(x) $(f-g)(x) = -2x^{2} - 8x +12$

Step-by-step explanation:

Here, the given function are:

$f(x) = 3x^{2} - 2x+ 4\\g(x) = 5x^{2} + 6x -8$

Now, simplifying for (f-g)(x) = f(x) - g(x):

$f(x) - g(x) = (3x^{2} - 2x+ 4) - (5x^{2} + 6x -8)$

$= 3x^{2} - 2x+ 4- 5x^{2} - 6x +8$

Doing operation on LIKE TERMS, we get

f(x) - g(x) = $( 3x^{2}- 5x^{2}) + (-2x - 6x) +( 4 +8) = -2x^{2} - 8x + 12$

Hence, for the given functions f(x) and g(x) $(f-g)(x) = -2x^{2} - 8x +12$

4 0

3 years ago

Leno4ka [110]

Answer:

$\frac{s^2-25}{(s^2+25)^2}$

Step-by-step explanation:

Let's use the definition of the Laplace transform and the identity given: $\mathcal{L}[t \cos 5t]=(-1)F'(s)$ with $F(s)=\mathcal{L}[\cos 5t]$ .

Now, $F(s)=\int_0 ^{+ \infty}e^{-st}\cos(5t) dt$ . Using integration by parts with u=e^(-st) and dv=cos(5t), we obtain that $F(s)=\frac{1}{5}\sin(5t)e^{-st} |_{0}^{+\infty}+\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt=\int_0 ^{+ \infty}e^{-st}\sin(5t) dt$ .

Using integration by parts again with u=e^(-st) and dv=sin(5t), we obtain that

$F(s)=\frac{s}{5}(\frac{-1}{5}\cos(5t)e^{-st} |_{0}^{+\infty}-\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}(\frac{1}{5}-\frac{s}{5}\int_0^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}-\frac{s^2}{25}F(s)$ .

Solving for F(s) on the last equation, $F(s)=\frac{s}{s^2+25}$ , then the Laplace transform we were searching is $-F'(s)=\frac{s^2-25}{(s^2+25)^2}$

3 0

2 years ago

i need help on math

dolphi86 [110]

X=2
2x-3=-x+3

add three to both sides
add 1x to each side
should be left with 3x=6
divide both sides by 3 to get x alone
your answer then is x=2

7 0

3 years ago