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3 years ago

9

1. What is the degree of the polynomial? t3 + 5t2 – 3t + 2

2 answers:

nignag [31]3 years ago

8 0

Answer:

degree 3

Step-by-step explanation:

The degree of a polynomial is determined by the largest exponent of the variable within the polynomial.

Given

t³ + 5t² - 3t + 2

The leading term t³ has exponent 3 , then

The polynomial is degree 3

gladu [14]3 years ago

7 0

I’m assuming that the first number is supposed to be raised by the power of 3. The degree of this polynomial would be 3 then if this is the case.

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yarga [219]

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Step-by-step explanation:

1). $\frac{2}{3}n-\frac{3}{4}n+\frac{1}{6}n+2\frac{2}{9}n$

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= $(\frac{3}{36}+\frac{72}{36}+\frac{8}{36})n$

= $\frac{83}{36}n$

= $2\frac{11}{36}n$

2). $\frac{2}{5}g-\frac{1}{6}-g+\frac{3}{10}g-\frac{4}{5}$

= $(\frac{2}{5}-1+\frac{3}{10})g-(\frac{1}{6}+\frac{4}{5})$

= $(\frac{4}{10}-\frac{10}{10}+\frac{3}{10})g-(\frac{5}{30}+ \frac{24}{30})$

= $(\frac{4-10+3}{10})g-(\frac{5+24}{30})$

= $\frac{-3}{10}g-\frac{29}{30}$

= $-\frac{3}{10}g-\frac{29}{30}$

3). $i+6i-\frac{3}{7}i+\frac{1}{3}h+\frac{1}{2}i-h+\frac{1}{4}h$

= $7i-\frac{3}{7}i+\frac{1}{2}i+\frac{1}{3}h-h+\frac{1}{4}h$

= $(7-\frac{3}{7}+\frac{1}{2})i+(\frac{1}{3}-1+\frac{1}{4})h$

= $(\frac{98}{14} -\frac{6}{14}+\frac{7}{14})i+(\frac{4}{12}-\frac{12}{12}+\frac{3}{12})h$

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6 0

3 years ago

Solve: −8x−7/ 3 =11

VladimirAG [237]

Answer: $x=-\frac{5}{3}$

Step-by-step explanation:

Given the equation $-8x-\frac{7}{3}=11$ , you need find the value of the variable x.

Then, you have to solve for x:

Add $\frac{7}{3}$ to both sides of the equation.

Divide by -8 to both sides of the equation.

Once you do this proccedure, you will get the value of the variable x.

Then:

$-8x-\frac{7}{3}+\frac{7}{3}=11+\frac{7}{3}$

$-8x=\frac{40}{3}\\\\\frac{-8x}{-8}=\frac{\frac{40}{3}}{-8}\\\\x=-\frac{5}{3}$

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3 years ago