All categories

2 years ago

1. What is the degree of the polynomial? t3 + 5t2 – 3t + 2

Mathematics

2 answers:

nignag [31]2 years ago

8 0

Answer:

degree 3

Step-by-step explanation:

The degree of a polynomial is determined by the largest exponent of the variable within the polynomial.

Given

t³ + 5t² - 3t + 2

The leading term t³ has exponent 3 , then

The polynomial is degree 3

gladu [14]2 years ago

7 0

I’m assuming that the first number is supposed to be raised by the power of 3. The degree of this polynomial would be 3 then if this is the case.

You might be interested in

brainliest answer <br>points question in the photo!!

ivolga24 [154]

..................#2

6 0

2 years ago

Escribe distintos repartos que se pondrían hacer de las cantidades siguientes asegúrate de hacer repartos equitativos y exactos

Keith_Richards [23]

Answer:

es 29.5?

Step-by-step explanation:

7 0

2 years ago

Please help. thx a bunch

Aleks [24]

0.55 HOPE THIS HELPS!

3 0

3 years ago

Read 2 more answers

Is the figure an example of parallel lines?

evablogger [386]

Parallel lines are a pair of lines that do not intersect

Therefore this is not an example of parallel lines because the lines intersect

The answer is C

5 0

2 years ago

Read 2 more answers

What is the length side of a triangle that has vertices at (-5, -1), (-5, 5), and (3, -1)?

Rasek [7]

The side lengths of triangle are 6 units, 8 units and 10 units.

<u>SOLUTION: </u>

Given that, we have to find what is the length side of a triangle that has vertices at (-5, -1), (-5, 5), and (3, -1)

We know that, distance between two points $P\left(x_{1}, y_{1}\right) \text { and } Q\left(x_{2}, y_{2}\right)$ is given by

$P Q=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}$

Now,

$\begin{array}{l}{\text { Distance between }(-5,-1) \text { and }(-5,5)=\sqrt{(-5-(-5))^{2}+(5-(-1))^{2}}} \\\\ {\qquad \begin{array}{l}{=\sqrt{(-5-(-5))^{2}+(5-(-1))^{2}}} \\\\ {=\sqrt{(0)^{2}+(5+1)^{2}}=\sqrt{(6)^{2}}=6} \\\\ {=\sqrt{(-5)^{2}+(5+1)^{2}+(5-(-1))^{2}}} \\\\ {=\sqrt{(-8)^{2}+(5+1)^{2}}=\sqrt{64+36}=\sqrt{100}=10} \\\\ {=\sqrt{(3-1)^{2}+(-1-(-1))^{2}}} \\\\ {=\sqrt{(5+3)^{2}+(0)^{2}}=\sqrt{(8)^{2}}=8}\end{array}}\end{array}$

8 0

2 years ago