I think the answer is M hope this helped
*∠A= 180° - 105°= 75°
Now we have to find x:
Since ∠M, ∠A, ∠T are angles of a triangle, we know that:
M∠ + ∠A + ∠T = 180°
180° - (2x + 27°) + 75° + x - 8° = 180°
180° - 2x - 27° + 75° + x - 8° = 180°
220° - 1x = 180°
- x = 180° - 220°
- x = - 40°
x = 40°
*∠M= 180° - (2x + 27°)
= 180° - 2 × 40° - 27°
= 180° - 80° - 27°
= 73°
*∠T= x - 8°
= 40° - 8
= 32°
Answer:
I believe the answer is <em>C</em>
Step-by-step explanation:
Answer:
Let’s denote X to be the number of white chips in the sample and E be the event that exactly half of the chips are white. Then,
a) Find α
α = P (reject H0 | H0 is true) = P (X ≥ 2|E)
= P (X = 2|E) + P (X = 3|E),
We took two case, as we can draw only only three chips with two or more white to reject H0, it means we can only take 2 white chips or 3, not more, we get solution
= (5C2 * 5C1)/10C3 + (5C3 * 5C0)/10C3
= 0.5
So, α = 0.5
b) Find β
i) Let E1 be the event that the urn contains 6 white and 4 red chips. (As given)
β = P (accept H0 | E1) = P (X ≤ 1|E1)
= (6C0 * 4C3)/10C3 + (6C1 * 4C2)/10C3
= 1/3
= 0.333
So, β = 0.333
i) Let E2 be the event that the urn contains 7 white and 3 red chips. (As given)
β = P (accept H0 | E2) = P (X ≤ 1|E2)
= (7C0 * 3C3)/10C3 + (7C1 * 3C2)/10C3
= 11/60
= 0.183
So, β = 0.183
22.
Alternate angles23.
4: (
, substitute b with 10 and a with 20 and you get 4.)
24.
0.28: 0.12 + 0.60 = 0.72. Probability is always out of 1, so 1 - 0.72 should give you the probability of losing, which is 0.28.
