3 years ago

Evaluate 3x^4+2x^2-5x+1 when x=3202

Mathematics

2 answers:

mixas84 [53]3 years ago

7 0

Answer:21

Step-by-step explanation:

Klio2033 [76]3 years ago

6 0

Answer:

315359990076847

Step-by-step explanation:

3x^4+2x^2-5x+1 when x=3202

replace the x's with 3202

3(3202)^4+2(3202)^2-5(3202)+1

solve the exponent first

3(105119989862416)+2(10252804)-5(3202)+1

then multiply

315359969587248+20505608-16010+1

add/subtract

315359990076847

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