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liberstina [14]
3 years ago
13

Evaluate 3x^4+2x^2-5x+1 when x=3202

Mathematics
2 answers:
mixas84 [53]3 years ago
7 0

Answer:21

Step-by-step explanation:

Klio2033 [76]3 years ago
6 0

Answer:

315359990076847

Step-by-step explanation:

3x^4+2x^2-5x+1 when x=3202

replace the x's with 3202

3(3202)^4+2(3202)^2-5(3202)+1

solve the exponent first

3(105119989862416)+2(10252804)-5(3202)+1

then multiply

315359969587248+20505608-16010+1

add/subtract

315359990076847

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Answer:

i hope it will help you

Step-by-step explanation:

Working capital management is how companies are able to manage finances and continue operations.

7 0
3 years ago
Given that an = 3an - 1 + 1, where a1 = 2, find the 3rd-6th terms of the sequence.
marishachu [46]
For the answer to the question above, <span>if 
a1 = 2, 
then 
a2 = 3a1 + 1 
a3 = 3a2 + 1 = 3
Then, we can finally solve for terms of sequence.
(3a1 + 1) + 1 = 9a1 + 4 = 9(2) + 4 = 22 

So the answer to your question is,
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8 0
3 years ago
Which type of individuals within a species is most likely to survive and reproduce.
nekit [7.7K]

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5 0
2 years ago
G^2 +23 when. g=6 please help
lapo4ka [179]

Answer:

59

Step-by-step explanation:

Substitute.

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4 0
4 years ago
I need math help. If youre solving a geometric sequence, the equation needed is An=A1Rn-1. If A1= 5 and R= -2. My question was "
CaHeK987 [17]

Answer:

Step-by-step explanation:

an = a1 * r^(n - 1)

a1 = first term = 5

r = -2

n = nth term of the sequence

so it starts with 5

second term is :

an = a1 * r^(n - 1)......for second term

a2 = 5 * -2^(2 - 1) =

a2 = 5 * -2^1

a2 = 5 * -2

a2 = -10

an = a1 * r^(n - 1)....looking for a3

a3 = 5 * -2^(3 - 1)

a3 = 5 * -2^2

a3 = 5 * 4

a3 = 20

an = a1 * r^(n - 1)....looking for a4

a4 = 5 * -2^(4 - 1)

a4 = 5 * -2^3

a4 = 5 * -8

a4 = - 40

an = a1 * r^(n - 1)...looking for a5

a5 = 5 * -2^(5 - 1)

a5 = 5 * -2^4

a5 = 5 * 16

a5 = 80

an = a1 * r^(n-1)...looking for a6

a6 = 5 * -2^(6 - 1)

a6 = 5 * -2^5

a6 = 5 * -32

a6 = -160

4 0
4 years ago
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