The coefficients in the balanced reaction
<u>4</u> Fe + <u>3</u> O₂ → <u>2</u> Fe₂O₃
represent the ratio of moles of each reactant to each product. That is, for every 4 moles of Fe and 3 moles of O₂, 2 moles of Fe₂O₃ are produced.
First convert the given amount of Fe into moles. Fe has a molar mass of 55.845 g/mol, so you have
42.7 g × (1/55.845 mol/g) = 0.765 mol
of Fe.
Find how many moles of Fe₂O₃ are produced given this much Fe and an abundant supply of O₂. Multiply the coefficients of the balanced reaction by 0.765/4 :
<u>0.765</u> Fe + <u>0.573</u> O₂ → <u>0.382</u> Fe₂O₃
Now convert the amount of Fe₂O₃ to grams. O has a molar mass of 15.999 g/mol, so Fe₂O₃ has a total molar mass of about
2 (55.845 g/mol) + 3 (15.999 g/mol) = 159.687 g/mol
Then the reaction would produce about
0.382 mol × (158.687 g/mol) ≈ 61.0 g
of Fe₂O₃.
Answer:
2 1/4
Step-by-step explanation:
hope this helps
A major arc is an arch of a circle having the measure greater than or equal to 180 degrees (pi radians)
Answer:
-18
Step-by-step explanation:
-xy^2 =
Let x=2 and y = -3
-(2) (-3)^2
-2 (9)
-18
Answer:
B
Step-by-step explanation:
