All categories

3 years ago

Define a major arc. How do you name a major arc?

Mathematics

2 answers:

vovikov84 [41]3 years ago

8 0

A major arc is an arc of a circle having measure greater than or equal to ( radians).

kogti [31]3 years ago

5 0

A major arc is an arch of a circle having the measure greater than or equal to 180 degrees (pi radians)

You might be interested in

What is absolute value?

pochemuha

Answer:

Absolute value means the distance between a number and 0.

Examples:

The absolute value of -7 is 7.

The absolute value of 5 is 5.

Key Concepts:

The absolute value sign is |x|, where x is any real number.

The absolute value removes any negative sign in front of a number.

8 0

3 years ago

Read 2 more answers

At the gas station, each liter of gas costs $ 3 $3dollar sign, 3, but there's a promotion that for every beverage you purchase y

IgorC [24]

Answer:

Yes! Our total savings on gas proportional to the number of beverages you purchase.

Step-by-step explanation:

Here, each liter of gas costs $3.

Every beverage you purchase you save $0.20.

So, if you purchase for $9, you will save 3*$0.20 = $0.60

So, this is proportional because when increase in purchase, there is proportional increase in savings.

6 0

3 years ago

The polygons below are similar. Find the value of y. 4.5 12 16 Guess: 16

elena55 [62]

I believe its 4.5
I could be wrong though

8 0

3 years ago

In ΔMNO, n = 78 cm, o = 14 cm and ∠M=12°. Find the length of m, to the nearest centimeter

STALIN [3.7K]

Answer:

Step-by-step explanation:

i calculated using https://www.calculator.net/triangle-calculator.html :/

5 0

2 years ago

Read 2 more answers

A brick is thrown upward from the top of a building at an angle of 250 above the horizontal, and with an initial speed of 15 m/s

mojhsa [17]

Answer:

(a) 25.08 m

(b) 2.05 m

Step-by-step explanation:

Let the height of the building be 'h'.

Given:

Angle of projection is, $\theta=25$ °

Initial speed is, $u=15\ m/s$

Time of flight is, $t=3.0\ s$

(a)

Consider the vertical motion of the brick.

Vertical component of initial velocity is given as:

$u_y=u\sin\theta\\\\u_y=15\sin(25)=6.34\ m/s$

Vertical displacement of the brick is equal to the height of the building.

So, vertical displacement = $-h$ (Negative sign implies downward motion)

Acceleration is due to gravity in the downward direction. So,

Acceleration is, $g=-9.8\ m/s^2$

Now, using the following equation of motion;

$-h=u_yt+\frac{1}{2}gt^2\\-h=6.34(3)-\frac{9.8}{2}(3)^2\\\\-h=19.02-44.1\\\\-h=-25.08\\\\h=25.08\ m$

Therefore, the building is 25.08 m tall.

(b)

Let the maximum height be 'H'.

At maximum height, the vertical component of velocity is 0 as the brick stops temporarily in the vertical direction.

So, $v_y=0\ m/s$

Now, using the following equation of motion, we have:

$v_y^2=u_y^2+2gH\\\\0=(6.34)^2-2\times 9.8\times H\\\\19.6H=40.2\\\\H=\frac{40.2}{19.6}=2.05\ m$

Therefore, the maximum height of the brick is 2.05 m.

5 0

3 years ago