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3 years ago

Define a major arc. How do you name a major arc?

Mathematics

2 answers:

vovikov84 [41]3 years ago

8 0

A major arc is an arc of a circle having measure greater than or equal to ( radians).

kogti [31]3 years ago

5 0

A major arc is an arch of a circle having the measure greater than or equal to 180 degrees (pi radians)

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The entire pink figure has been transformed to create the new blue image. Describe the transformation that has taken place.

Leno4ka [110]

Answer:

D. (bottom right)

Step-by-step explanation:

If there is a line where y = x, that means that y and x can both equal 1, 2, 3, -1, -2, -3, etc. They are just always the same. This line, then, would pass through (just for example) (-4, -4) and (4, 4). If you reflect the pink figure across that line, you will get the blue figure. Hope this helps!

6 0

2 years ago

I HAVE A COMMON ASSESSMENT HELP PLZ!

Kitty [74]

Answer:

A. Reflection

Step-by-Step Explanation:

you're reflecting the line across the x-axis, and that transforms f(x) into g(x).

3 0

3 years ago

What is the equation of the line that passes through the points ( 5,-2) and (-5,0)

Novosadov [1.4K]

Answer:

y=-1/5x-1

Step-by-step explanation:

4 0

2 years ago

Find the perimeter of the following triangle.

pashok25 [27]

Hello!

To find the perimeter of the triangle, we need to find the length of all the sides using the distance formula.

The distance formula is: $d =\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ .

First, we can find the distance between the points (-3, -1) and (2, -1). The point (-3, -1) can be assigned to $(x_{1},y_{1})$ , and (2, -1) is assigned to $(x_{2},y_{2})$ . Then, substitute the values into the formula.

$d =\sqrt{(2 - (-3))^{2}+ (-1 - (-1))^{2}}$

$d =\sqrt{5^{2}+0^{2}}$

$d =\sqrt{25} = 5$

The distance between the points (-3, -1) and (2, -1) is 5 units.

Secondly, we need to find the distance between the points (2, 3) and (2, -1). Assign those points to $(x_{1},y_{1})$ and $(x_{2},y_{2})$ , then substitute it into the formula.

$d =\sqrt{(2 - 2)^{2}+ (-1 - 3)^{2}}$

$d =\sqrt{0^{2}+(-4)^{2}}$

$d =\sqrt{16} = 4$

The distance between the two points (2, 3) and (2, -1) is 4 units.

Finally, we use the distance formula again to find the distance between the points (-3, -1) and (2, 3). Remember the assign the ordered pairs to $(x_{1},y_{1})$ and $(x_{2},y_{2})$ and substitute!

$d =\sqrt{(2 -(-3))^{2}+ (3 - (-1))^{2}}$