If the degree of numerator and denominator are equal, then limit will be leading coefficient of numerator divided by the leading coefficient of denominator.

So then the limit would be 3/1 = 3.

Alternatively,

$\displaystyle \lim_{x\to\infty}\dfrac{3x^2+6}{x^2-4}=\displaystyle \lim_{x\to\infty}\dfrac{3x^2+6}{x^2-4}\cdot\dfrac{1/x^2}{1/x^2}=\lim_{x\to\infty}\dfrac{3+\frac6{x^2}}{1-\frac4{x^2}} = \dfrac{3+0}{1-0}=\boxed{3}$

Hope this helps.

5 0

2 years ago

Help please !!!!!!!!!

wlad13 [49]

Answer:

Step-by-step explanation:

4 0

2 years ago

A locker combination has four nonzero digits. If no digit can be repeated and the first three digits are 1-2-3, what is the prob

Elis [28]

The probability that the fourth digit is 4 is 1/6.

<h3>What is the probability?</h3>

Probability is used to calculate the odds that a random event would happen. The probability the event occurs is 1 and the probability that the event does not occur is 0.

Probability the number is 4 = 1 / possible numbers

Possible numbers = 4, 5, 6, 7, 8, 9,

= 1/6

To learn more about probability, please check: brainly.com/question/13234031

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6 0

2 years ago