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Lubov Fominskaja [6]

3 years ago

8

Which of the following is a reason for needing to acquire a 1040X form?

1 answer:

LenaWriter [7]3 years ago

4 0

Answer: If you ever discover an error on a tax return, realize you qualify for deductions or credits you didn't take, or forgot to include some income, you may be able to amend your return by filing a Form 1040X.

Step-by-step explanation:

You might be interested in

What is 10 1/3 x 1/4? that is, what is ten and one third times one fourth?

Phantasy [73]

Answer: 31/12, or 2 7/12

Step-by-step explanation: The answer is actually very simple. All you have to do is to simplify 10 1/3 into 31/3, as 10x3+1=31. Then, you have to multiply 31/3 with 1/4. Do a simple fraction multiplication, and you get 31/12, or 2 7/12 if your teacher is asking for a mixed number. Sometimes simplifying is better

6 0

3 years ago

3 +17 p + 2 - P<br> Simply each expression by combing like terms

natita [175]

3+17p+2-p
=3+2+17p-p
=5+16p

hope this helps!!

7 0

2 years ago

Find+the+positive+value+for+α+if+the+radius+of+the+circle+3x^2+3y-6αx+12y-3α=0+is+4

Alik [6]

Answer:

$\alpha=3$

Step-by-step explanation:

<u>Equation of a Circle</u>

A circle of radius r and centered on the point (h,k) can be expressed by the equation

$(x-h)^2+(y-k)^2=r^2$

We are given the equation of a circle as

$3x^2+3y^2-6\alpha x+12y-3\alpha=0$

Note we have corrected it by adding the square to the y. Simplify by 3

$x^2+y^2-2\alpha x+4y-\alpha=0$

Complete squares and rearrange:

$x^2-2\alpha x+y^2+4y=\alpha$

$x^2-2\alpha x+\alpha^2+y^2+4y+4=\alpha+\alpha^2+4$

$(x-\alpha)^2+(y+2)^2=r^2$

We can see that, if r=4, then

$\alpha+\alpha^2+4=16$

Or, equivalently

$\alpha^2+\alpha-12=0$

There are two solutions for $\alpha$ :

$\alpha=-4,\ \alpha=3$

Keeping the positive solution, as required:

$\boxed{\alpha=3}$

8 0

3 years ago

I really need help rn T_T plz help me out!

pshichka [43]

Answers:

The lengths of sides PQ and RS are <u> 13 </u>
The lengths of sides QR and SP are <u> </u><u>20 </u>

This is a 13 by 20 rectangle.

============================================================

Explanation:

Refer to the drawing below.

Let x be the length of side SP. Since we're dealing with a rectangle, the opposite side is the same length. Side QR is also x units long.

We're told that RS = SP - 7 which is the same as saying RS = x-7

We also know that PQ = x-7 as well because PQ is opposite side RS.

In short, we have these four sides in terms of x

PQ = x-7
QR = x
RS = x-7
SP = x

as shown in the drawing. The four sides add up to the perimeter of 66.

PQ+QR+RS+SP = perimeter

PQ+QR+RS+SP = 66

(x-7)+x+(x-7)+x = 66

4x-14 = 66

4x = 66+14

4x = 80

x = 80/4

x = 20

Use this x value to find the unknown side lengths.

PQ = x-7 = 20-7 = 13
QR = x = 20
RS = x-7 = 20-7 = 13
SP = x = 20

In short, this is a 13 by 20 rectangle.

-----------------

Check:

perimeter = side1+side2+side3+side4

perimeter = PQ+QR+RS+SP

perimeter = 13+20+13+20

perimeter = 33+33

perimeter = 66

The answer is confirmed.

4 0

2 years ago

Heyyyyy pleasse help me please please and thank you

dimulka [17.4K]

Answer:

x ≈ 33.1°

Step-by-step explanation:

Using the tangent ratio in the right triangle

tan x = $\frac{opposite}{adjacent}$ = $\frac{125}{192}$ , then

x = $tan^{-1}$ ( $\frac{125}{192}$ ) ≈ 33.1° ( to the nearest tenth )

7 0

2 years ago