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stira [4]
3 years ago
9

Can someone help with this explain the steps pls

Mathematics
2 answers:
kipiarov [429]3 years ago
8 0

Answer:

first one is x=-y+11 and the second is x=−y/2 +19/2

Step-by-step explanation:

Step 1 for #2: Subtract y from both sides.

Step 2 for #2: Divide both sides by 2.

Step 1 for #1: Subtract y from both sides.

Tju [1.3M]3 years ago
7 0

Answer:

the first one add Y to both sides so it would be x=y+11

Step-by-step explanation:

and the second one would be  add y to both sides 2x + y + -y = 19 + -y =

2x= -y + 19 the divide both sides by 2 and once you do that you should get   x= \\\frac{-1}{2} y + \frac{19}{2}

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Which equation is parallel to the line LaTeX: y=\frac{1}{2}x+3y = 1 2 x + 3and passes through the point (10, -5)?
sukhopar [10]

Answer:

Equation\ of\ line:\ y=\frac{1}{2}x-10

Step-by-step explanation:

Let\ the\ required\ equation\ is\ y=mx+c\\\\where\ m\ is\ the\ slope\ of\ the\ equation\ and\ c\ is\ y-intercept\\\\It\ is\ parallel\ to\ the\ equation\ y=\frac{1}{2}x+3\\\\Hence\ slope\ of\ these\ two\ lines\ will\ be\ same.\\\\Slope\ of\ y=\frac{1}{2}x+3\ is\ \frac{1}{2}\\\\Hence\ slope\ of\ y=mx+c\ is\ \frac{1}{2}\Rightarrow m=\frac{1}{2}\\\\Equation:y=\frac{1}{2}x+c\\\\Line\ passes\ through\ (10,-5).\ Hence\ this\ point\ satisfies\ the\ equation\ of\ line.\\\\-5=\frac{1}{2}\times 10+c

-5=-5+c\\\\c=-10

Equation\ of\ line:\ y=\frac{1}{2}x-10

8 0
3 years ago
I need help solving this
pentagon [3]
Y=mx+b where m=slope=(dy/dx) and b=y-intercept (value of y when x=0)

You have two points...(1,-2),(3,2) so

m=(y2-y1)/(x2-x1)=(2--2)/(3-1)

m=4/2=2 now that you have the slope...

y=2x+b, you can use either point to solve for the y-intercept, I'll use (3,2)

2=2(3)+b

2=6+b

b=-4 so the line is:

y=2x-4
5 0
3 years ago
A school is selling tickets to a drama performance. On the first day of ticket sales the school sold 3 adult tickets and 1 child
baherus [9]

Answer:

System of linear equations

\left\{\begin{matrix} 3a+c=38 \\\\   3a+2c=52 \end{matrix}\right.

a: adult ticket price and c: child ticket price

Step-by-step explanation:

This system of equations can be used to find the price of the adult and child tickets.

We have two equations (one for each day) and two unknowns (adult ticket price and child ticket price).

Let a: adult ticket price and c: child ticket price,

we have for the first day that 3 adult tickets and 1 child ticket adds $38:

3a+1c=38

and for the second day we have that 2 adult tickets and 2 child tickets adds $52:

3a+2c=52

If we write this as a system of equations, we have:

\left\{\begin{matrix} 3a+c=38 \\\\   3a+2c=52 \end{matrix}\right.

4 0
3 years ago
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