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3 years ago

Erik works 55 hours a week making $12.50 hour? His employer pays time and a half for hours over 40. Find his gross pay.

Mathematics

1 answer:

UNO [17]3 years ago

6 0

Answer:

781.25

Step-by-step explanation:

Regular pay = 40*12.50 = 500.00

Overtime = 15*12.5*1.5 = 281.25

Gross pay = 500.00 + 281.25 = 781.25

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The ordered pair (3,9) is located in what quadrant? Quadrant I Quadrant II Quadrant III Quadrant IV 2 points QUESTION 2 If you m

galben [10]

For the first question the answer would be the first quadrant
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8 0

3 years ago

Read 2 more answers

4(v+7) = -6(3v-4) +8v<br>

xxTIMURxx [149]

Answer:

v=−27

Step-by-step explanation:

Since v is on the right side of the equation, switch the sides so it is on the left side of the equation.

−6(3v−4)+8v=4(v+7)

Simplify −6(3v−4)+8v

−10v+24=4(v+7)

Simplify 4(v+7).

−10v+24=4v+28

Move all terms containing v to the left side of the equation.

−14v+24=28

Move all terms not containing v to the right side of the equation.

−14v=4

Divide each term by −14 and simplify.

v=−27

The result can be shown in multiple forms.

Exact Form:

v=−27

6 0

2 years ago

7- a. What is the radius of the circle with center (3,10) that passes through (12,12)?

loris [4]

Answer: a. Radius of circle = $\sqrt{85}$

b. The equation of this circle : $(x-3)^2+(y-10)^2=85$

Step-by-step explanation:

Given : Center of the circle = (3,10)

Circle is passing through (12,12).

a. To find the radius we apply distance formula (∵ Radius is the distance from center to any point ion the circle.)

Radius of circle = $\sqrt{(12-3)^2+(12-10)^2}$

Radius of circle = $\sqrt{(9)^2+(2)^2}=\sqrt{81+4}=\sqrt{85}$

i.e. Radius of circle = $\sqrt{85}$

b. Equation of a circle = $(x-h)^2+(y-k)^2=r^2$ , where (h,k)=Center and r=radius of the circle.

Put the values of (h,k)= (3,10) and r= $\sqrt{85}$ , we get

$(x-3)^2+(y-10)^2=(\sqrt{85})^2$

$(x-3)^2+(y-10)^2=85$

∴ The equation of this circle : $(x-3)^2+(y-10)^2=85$

6 0

3 years ago

Prove that sin^4x + cos^4x= sinxcosx

yKpoI14uk [10]

Answer:

(the relation you wrote is not correct, there may be something missing, so I will simplify the initial expression)

Here we have the equation:

$sin^4(x) + cos^4(x)$

We can rewrite this as:

$(sin^2(x))^2 + (cos^2(x))^2$

Now we can add and subtract cos^2(x)*sin^2(x) to get:

$(sin^2(x))^2 + (cos^2(x))^2 + 2*cos^2(x)*sin^2(x) - 2*cos^2(x)*sin^2(x)$

We can complete squares to get:

$(cos^2(x) + sin^2(x))^2 - 2*cos(x)^2*sin(x)^2$

and we know that:

cos^2(x) + sin^2(x) = 1

then:

$1 - 2*sin(x)^2*cos(x)^2$

This is the closest expression to what you wrote.

We also know that:

sin(x)*cos(x) = (1/2)*sin(2*x)

If we replace that, we get:

$1 - \frac{sin^2(2*x)}{2}$

Then the simplification is:

$cos^4(x) + sin^4(x) = 1 - \frac{sin^2(2*x)}{2}$

7 0

2 years ago

Limit as x approaches 0 of. (sin3xsin5x)/x^2

OLga [1]

The limit of the function <span>( sin3x sin5x ) / x^2 as x approaches zero is evaulated by substituting the function by zero. Since the answer is zero / zero which is indeterminate. Using L'hopitals rule, we derive separately the numerator and the denominator. we all know that sin 5x and sin 3x are equal to zero. Upon teh first derivative, the answer is still zero / zero. We derive further until the function has a denominator of 2 and a numerator still equal to zero. Since the answer is now zero/ 2 or zero not zero/zero, the limit then is equal to zero.</span>

4 0

2 years ago