For complex number, the magnitude is pretty straight forward:
sqrt(6^2 + 2^2) = sqrt(40)
For any a + bi, the magnitude will be sqrt(a^2 + b^2)
Step-by-step explanation:
x + y = 9. => 2x + 2y = 18.
2x + 2y = 18
- (2x - 3y = -12)
=> 5y = 30, y = 6.
Therefore x + (6) = 9, x = 3.
The solution is x = 3 and y = 6.
Since the triangle is a right triangle at point B, then line AB is perpendicular to line BC.
For perpendicular lines, the product of their slopes is -1.
Slope of AB = (5 - 0)/(2 - 5) = 5/-3 = -5/3
Slope of BC = (y - 5)/(7 - 2) = (y - 5)/5
-5/3(y - 5)/5 = -1
-5(y - 5)/15 = -1
-5(y - 5) = -15
y - 5 = 3
y = 3 + 5 = 8
Therefore, the y-coordinate of point C is 8.
A + B + C = 180
x + 2x + 2 + 3x + 4 = 180
6x + 6 = 180
6x = 174
x = 29
<h3>I'll teach you how to solve (sqrt 9)^2 +5</h3>
-------------------------------------------------
(sqrt 9)^2 +5
Apply radical rule:
(9^1/2)2
Apply exponent rule:
9^1/2*2
1/2* 2= 1
=9
9+5= 14
Your Answer Is 14
plz mark me as brainliest :)
