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pochemuha
3 years ago
12

Suppose that a digitized TV picture is to be transmitted from a source that uses a matrix of 480 * 500 picture elements (pixels)

, where each pixel can take on one of 32 intensity values. Assume that 30 pictures are sent per second. (This digital source is roughly equivalent to broadcast TV standards that have been adopted.) Find the source rate R (bps).
Mathematics
1 answer:
attashe74 [19]3 years ago
8 0

Answer:

36,000,000 bps

Step-by-step explanation:

Matrix of 480 by 500 = 480 X 500 = 240,000 pixels

Intensity values per pixel = 32. This simply means the color variations in this TV.

The bit per pixel for an intensity value of 32 is 5 (That's 2 raised to the power of 5)

Pictures sent per second = 30

Source rate R (bps) = Total number of pixels in the matrix X bit per pixel X Number of pictures sent per second.

Source rate R (bps) = 240,000 X 5 X 30 = 36,000,000 bps

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8 0
3 years ago
Does anyone know how to do this
Julli [10]
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5 0
3 years ago
Read 2 more answers
Laurie buys four bags of candy with 10 pieces of candy in each bag. Her father then gives her 5 more pieces of candy. Laurie wan
Alborosie
Your Question:
<span>Laurie buys four bags of candy with 10 pieces of candy in each bag. Her father then gives her 5 more pieces of candy. Laurie wants to give as much of her candy as she can to each of her six friends, and she wants to make sure they each get an equal number of pieces. How many pieces will be left over, if any, after Laurie gives her friends the candy?
My Answer:
If Laurie has four bags with ten pieces in each bag, and if her father gives her five more pieces,  she would have forty-five pieces and if she has six friends and wants to share it equally with six friends. Each friend would get 7 pieces.
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3 years ago
A rectangle initially has width 7 meters and length 10 meters and is expanding so that the area increases at a rate of 8 square
Tems11 [23]

Answer:

The length of rectangular is increasing at a rate 0.5714 meters per hour.

Step-by-step explanation:

We are given the following in the question:

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