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3 years ago

Please help me out!

Mathematics

1 answer:

shtirl [24]3 years ago

6 0

Lets start by figuring out the values of all.

A. pi + 1 = 4.1415
B. square root of 24 = 4.8989
C. q/2
D. 4.222

Judging by these, we can conclude that the highest value is that of B. I hope this helps!

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What are the domain and range of this relation? 5 4 2 1 -5-4-3-2-10

marishachu [46]

The domain in a relation y(x) is the set of values for which the relation is defined (the values on x, where y is defined)

In this relation the values wich the relation is defined is: the coordinates of x where there are a point:

Domain: -1, 0, 3

The range in a relation y(x) is the set of all the values that y(x) takes (the values of y)

In this relation the values that takes y(x) are the coordinates of y where there are a point:

Range: -3, -1, 0

8 0

1 year ago

Which is a true statement about angles 1 and 2? O the two angles are supplementary

lana66690 [7]

C neither
Thank you hope this helps

5 0

3 years ago

Let f(x) = tan(x) - 2/x. Let g(x) = x^2 + 8. What is f(x)*g(y)?

Tema [17]

Answer:

$f(x)\times g(y)=y^2tan(x)+8tan(x)-\frac{2y^2}{x}-\frac{16}{x}$

Step-by-step explanation:

We are given that

$f(x)=tan(x)-\frac{2}{x}$

$g(x)=x^2+8$

We have to find $f(x)\times g(y)$

To find the value of $f(x)\times g(y)$ we will multiply f(x) by g(y)

$g(y)=y^2+8$

Now,

$f(x)\times g(y)=(tanx-\frac{2}{x})(y^2+8)$

$f(x)\times g(y)=tan(x)(y^2+8)-\frac{2}{x}(y^2+8)$

$f(x)\times g(y)=y^2tan(x)+8tan(x)-\frac{2y^2}{x}-\frac{16}{x}$

Hence,

$f(x)\times g(y)=y^2tan(x)+8tan(x)-\frac{2y^2}{x}-\frac{16}{x}$

5 0

3 years ago

In Argentina, a cow on a ranch is expected to need an average of 4200 m2

nika2105 [10]

The cows of Argentina needs an approximate area of 4200 m² for grazing, and there is a total of 4500 cows.

And we are asked to find the total area of their grazing but in hectares. So, we can write:

$1 \: cow = 4200 \: {m}^{2}$

Then, for 4500 cows:

$4500 \: cows = 4200 \: {m}^{2} \times 4500$

$4500 \: cows = 18900000 \: m {}^{2}$

We know that, 1 hectares = 10000 m² = 10⁴ m²

Then let the area of the field be x in hectares:

$1 \: hectare = 10000 \: {m}^{2}$

$x \: hectare = 18900000 \: {m}^{2}$

Then, putting them in proportion, We will get:

$x = \dfrac{18900000}{10000} hectares$

$x = \boxed{ 1890 \: hectares}$

So, the total area in hectares = 1890 hectares.

And we are done !!

#CarryOnLearning

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6 0

3 years ago

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Marina86 [1]

Answer:

could you translate it

Step-by-step explanation:

8 0

3 years ago

Please help me out!​

Please help me out!