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grigory [225]
3 years ago
13

Find the greatest common factor of the following monomials. 45s^6t^5 6s^2t^3 12s^4t^4

Mathematics
1 answer:
Cloud [144]3 years ago
3 0
45s^6t^5=3\cdot\boxed{3}\cdot5\cdot \boxed{s^2}\cdot s^4\cdot\boxed{ t^3}\cdot t^2\\\\6s^2t^3=2\cdot\boxed{3}\cdot \boxed{s^2}\cdot \boxed{t^3} \\\\12s^4t^4=2\cdot2\cdot\boxed{3}\cdot \boxed{s^2}\cdot s^2\cdot \boxed{t^3}\cdot t\\\\GCF(45s^6t^5;\ 6s^2t^3;\ 12s^4t^4)=3s^2t^3
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The vertex formation of a parabola is x = 8(y- 1)2-76.
Gennadij [26K]

Answer:

\boxed{x=8y^2-16y-68}

Step-by-step explanation:

Hello, please consider the following.

x=8(y- 1)^2-76\\\\x=8(y^2-2y+1)-76\\\\x=8y^2-16y+8-76\\\\\boxed{x=8y^2-16y-68}

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

6 0
3 years ago
Read 2 more answers
The 12th term of the arithmetic sequence is 10.5. The 18th term of this sequence is 13.5. Find the common difference and the fir
xxMikexx [17]

Answer:

common difference is 0.5

first term is 5

Step-by-step explanation:

<em>use </em><em>the </em><em>formula</em><em> for</em><em> </em><em>the</em><em> </em><em>nth </em><em>term </em><em>of </em><em>an </em><em>ap </em><em>Tn=</em><em>a+</em><em>(</em><em>n-1)</em><em>d</em>

<em>T12=</em><em>1</em><em>0</em><em>.</em><em>5</em>

<em>T18=</em><em>1</em><em>3</em><em>.</em><em>5</em>

<em>therefore</em><em> </em><em>come </em><em>up </em><em>with </em><em>two </em><em>equations</em>

<em>T12=</em><em>a+</em><em>(</em><em>1</em><em>2</em><em>-</em><em>1</em><em>)</em><em>d</em>

<em>1</em><em>0</em><em>.</em><em>5</em><em>=</em><em>a+</em><em>1</em><em>1</em><em>d</em><em>(</em><em>1</em><em>s</em><em>t</em><em> </em><em>equation</em><em>)</em>

<em>T18</em><em>=</em><em>a+</em><em>(</em><em>1</em><em>8</em><em>-</em><em>1</em><em>)</em><em>d</em>

<em>1</em><em>3</em><em>.</em><em>5</em><em>=</em><em>a+</em><em>1</em><em>7</em><em>d</em><em>(</em><em>2</em><em>n</em><em>d</em><em> </em><em>equation</em><em>)</em>

<em>then </em><em>solve </em><em>both </em><em>as </em><em>a </em><em>simultaneous</em><em> </em><em>equation</em>

<em>a+</em><em>1</em><em>1</em><em>d</em><em>=</em><em>1</em><em>0</em><em>.</em><em>5</em>

<em>a+</em><em>1</em><em>7</em><em>d</em><em>=</em><em>1</em><em>3</em><em>.</em><em>5</em>

<em> </em><em> </em><em> </em><em> </em><em>-6d/</em><em>-</em><em>6</em><em>=</em><em>-</em><em>3</em><em>/</em><em>-</em><em>6</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>d=</em><em>0</em><em>.</em><em>5</em>

<em>use </em><em>one </em><em>of</em><em> the</em><em> </em><em>equations</em><em> </em><em>to </em><em>find </em><em>the </em><em>first</em><em> </em><em>term</em>

<em>a+</em><em>1</em><em>1</em><em>(</em><em>0</em><em>.</em><em>5</em><em>)</em><em>=</em><em>1</em><em>0</em><em>.</em><em>5</em>

<em>a+</em><em>5</em><em>.</em><em>5</em><em>=</em><em>1</em><em>0</em><em>.</em><em>5</em>

<em>a=</em><em>1</em><em>0</em><em>.</em><em>5</em><em>-</em><em>5</em><em>.</em><em>5</em>

<em>a=</em><em>5</em>

<em>I </em><em>hope </em><em>this </em><em>helps</em>

<em>please </em><em>mark</em><em> </em><em>as </em><em>brainliest</em>

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Tony wants to buy 2.3 pounds of dried berries and 2.6 pounds of trail mix. How much will he spend?
AURORKA [14]
How much dose it cost per pound?
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2 years ago
A class consists of 23 women and 83 mean. If a student is random selected, what is the probability that the student is a woman?
slavikrds [6]

Answer:

P(Woman) = \frac{23}{106}

Step-by-step explanation:

Given

Women = 23

Men = 83

Required

P(Woman)

This is calculated as the number of women divided by the population of the class

i.e.

P(Woman) = \frac{Women}{Women + Men}

So, we have:

P(Woman) = \frac{23}{23+83}

P(Woman) = \frac{23}{106}

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