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Nikitich [7]
2 years ago
14

Please solve this question

Mathematics
1 answer:
boyakko [2]2 years ago
7 0

Answer:

Gud morning friend

Step-by-step explanation:

Sorry friend I don't know

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The sum of Eric’s and Bob’s weights is 9 times the difference of their weights. The positive difference of their weights is also
Pie

Answer:

<u>150</u>

Step-by-step explanation:

So I will shorten Eric, and Bob's names as E, and B.

So the equations are this

B-E = B+E - 240, E as Eric, and B as Bob, and this E+B=9(E-B)

Move the variables and you get

-2E =- 240

Just divide them both by -2

and E=120

So when we know the value of E we can just plug it into the 1st question

120+B=9B+1080

Moves the Variables and numbers to the other side

8B=1200

1200/8= 150

B=150

There is Bob's weight

6 0
2 years ago
Find the area and the circumference of a circle with radius 6cm.
OLga [1]

Answer:

Step-by-step explanation:

The formula for determining the circumference of a circle is expressed as

Circumference = 2πr

Where

r represents the radius of the circle

π is a constant whose value is 3.14

From the information given,

Radius = 6 cm

Therefore,

Circumference = 2 × 3.14 × 6

Circumference = 37.68 cm

The formula for determining the area of a circle is expressed as

Area = πr²

Area = 3.14 × 6² = 113.04 cm²

4 0
3 years ago
A bean plant grows at a constant rate for a month. After 10 days, the plant is
777dan777 [17]

Answer:

B. y - 35 = 2(x - 10)

Step-by-step explanation:

The height of the plant, y, after x days could be modeled by the equation

<h3>y-y0=k(x-xo)     (1),</h3><h3>where y0 was the initial height at 'x0'th. day, and k is the constant of proportionality.</h3><h3>From equation (1), k could be evaluated as follows:</h3><h3>k=(y-y0)/(x-x0) </h3><h3>From the problem statement, we may determine k by plugging in the given values, e.g. y0= 35, x0=10, y=55, x=20.</h3><h3>Thus,</h3><h3>k=(55-35)/(20-10)=2</h3><h3>Therefore, the model equation becomes</h3><h3>y-35=2(x-10)</h3><h3></h3>

6 0
3 years ago
In 2000 the total amount of gamma ray bursts was recorded at 6.4 million for a city. In 2005, the same survey was made and the t
ratelena [41]

Let's assume

It started in 2000

so, t=0 in 2000

P_0=6.4million

we can use formula

P(t)=P_0 e^{rt}

we can plug value

P(t)=6.4 e^{rt}

In 2005, the same survey was made and the total amount of gamma ray bursts was 7.3 million

so, at t=2005-2000=5

P(t)=7.3 million

we can plug value and then we can solve for r

7.3=6.4 e^{r*5}

r=0.02632

now, we can plug back

P(t)=6.4 e^{0.02632t}

now, we have

P(t)=1 billion =1000 million

so, we can set it and then we can solve for t

1000=6.4 e^{0.02632t}

t=191.924

approximately

t=192

Year is 2000+192

year is 2192................Answer

4 0
3 years ago
If It is known that 5
makkiz [27]
Could u give the rest of the question?
7 0
2 years ago
Read 2 more answers
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