Ask question

Ask question

All categories

3 years ago

7

Which of these strategies would eliminate a variable in the system of equations? \begin{cases} 6x + 5y = 1 \\\\ 6x - 5y = 7 \end

{cases} ⎩ ⎪ ⎪ ⎨ ⎪ ⎪ ⎧ 6x+5y=1 6x−5y=7

1 answer:

IRISSAK [1]3 years ago

3 0

Answer:

x = 0.667 and y = -0.6

Step-by-step explanation:

Given that,

6x + 5y = 1 ....(1)

6x - 5y = 7 ...(2)

We need to solve the above equations.

Subtract equations (1) and (2)

6x + 5y -(6x - 5y) = 1-7

6x+5y-6x+5y = -6

10y=-6

y = -0.6

Put the value of y in equation (1).

6x + 5(-0.6) = 1

6x = 1-5(-0.6)

6x = 4

x = 0.667

Hence, first step is to subtract equation (1) and (2) then put the value of y in equation (1).

You might be interested in

It has to do with slopes or something

Ostrovityanka [42]

What is it that I am supposed to be doing?

4 0

3 years ago

URGENT!!<br>Find the circumference of the wheel using the formula you found in part E. (C = 2πr)

ddd [48]

Answer:

69.08

Step-by-step explanation:

first substitute the values of pi 3.14 in the formula c and r 11 inches = 2πr to find c = 2 × 3.14 × 11 inches = 69.08 inches. the circumference is

4 0

2 years ago

Divide. (18x^3 + 12x^2 - 3x) ÷ 6x^2

nlexa [21]

$\bold{[ \ Answer \ ]}$

$\boxed{\bold{\frac{x^3\left(6x^2+4x-1\right)}{2}}}$

$\bold{[ \ Explanation \ ]}$

$\bold{Divide: \ \left(18x^3\:+\:12x^2\:-\:3x\right)\:\div \:6x^2}$

$\bold{-------------------}$

$\bold{Rewrite}$

$\bold{18x^3+12x^2-3x \ = \ x^2\frac{x\left(6x^2+4x-1\right)}{2}}$

$\bold{Rewrite}$

$\bold{x^2\frac{x\left(6x^2+4x-1\right)}{2}}$

$\bold{Multiply \ Fractions \ (a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c})}$

$\bold{\frac{x\left(6x^2+4x-1\right)x^2}{2}}$

$\bold{Rewrite}$

$\bold{x\left(6x^2+4x-1\right)x^2 \ = \ x^3\left(6x^2+4x-1\right)}$

$\bold{Simplify}$

$\bold{\frac{x^3\left(6x^2+4x-1\right)}{2}}$

$\boxed{\bold{[] \ Eclipsed \ []}}$

3 0

3 years ago

Read 2 more answers

Is 3,611,756 divisible by 9?<br><br> YES or NO<br><br> HELP ME PLZ!<br><br> T^T

Komok [63]

Answer:

NO IT IS NOT

Step-by-step explanation:

LOOK IN THE CALUCULATOR

6 0

3 years ago

Read 2 more answers

Write the equation of the quadratic function that passes through the points (-1, 1), (1, 5), and (2,10).

Serjik [45]

Answer:

$\displaystyle f(x)=x^2+2x+2$

Step-by-step explanation:

<u>System Of Linear Equations </u>

In this problem, we'll need to solve a 3x3 system of linear equations because we have three unknowns and three conditions.

We are required to find the equation of the quadratic function that passes through the points (-1, 1), (1, 5), and (2,10)

The general quadratic function can be written as

$\displaystyle f(x)=ax^2+bx+c$

We need to find the values of a,b, and c. Let's use the first condition, i.e. f(-1)=1

$\displaystyle f(-1)=a(-1)^2+b(-1)+c$

$\displaystyle f(-1)=a-b+c$

$\displaystyle a-b+c=1.....[eq\ 1]$

Now we use the second condition f(1)=5

$\displaystyle f(1)=a(1)^2+b(1)+c$

$\displaystyle f(1)=a+b+c$

$\displaystyle a+b+c=5.......[eq\ 2]$

Finally, we use the third condition f(2)=10

$\displaystyle f(2)=a(2)^2+b(2)+c$

$\displaystyle f(2)=4a+2b+c$

$\displaystyle 4a+2b+c=10....[eq\ 3]$

We put together eq 1, eq 2, and eq 3 to form the system

$\displaystyle \left\{\begin{matrix}a-b+c=1\\ a+b+c=5\\ 4a+2b+c=10\end{matrix}\right.$

Adding the first two equations we have

$\displaystyle 2a+2c=6$

$\displaystyle a+c=3$

And also

$\displaystyle b=2$

Using the above equation and the value of b in the third equation, we have

$\displaystyle \left\{\begin{matrix}a+c=3\\ 4a+c=6\end{matrix}\right.$

Subtracting the first equation from the second

$\displaystyle 3a=3$

$\displaystyle a=1$

And therefore

$\displaystyle c=2$

Now we have all the values, the quadratic function is

$\displaystyle \boxed{f(x)=x^2+2x+2}$

6 0

3 years ago