You have to give them the same denominator so multiply 11/12 by 4 and 3/16 by 3. giving you 44/48 and 9/48. then divied 44 by 9 giving you 4.8888
there for there are 4 whole 3/16 sections of the 11/12 board
The sum of all the even integers between 99 and 301 is 20200
To find the sum of even integers between 99 and 301, we will use the arithmetic progressions(AP). The even numbers can be considered as an AP with common difference 2.
In this case, the first even integer will be 100 and the last even integer will be 300.
nth term of the AP = first term + (n-1) x common difference
⇒ 300 = 100 + (n-1) x 2
Therefore, n = (200 + 2 )/2 = 101
That is, there are 101 even integers between 99 and 301.
Sum of the 'n' terms in an AP = n/2 ( first term + last term)
= 101/2 (300+100)
= 20200
Thus sum of all the even integers between 99 and 301 = 20200
Learn more about arithmetic progressions at brainly.com/question/24592110
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Answer:
Step-by-step explanation:
Ashley's page count is ...
P = 10D
Carly's page count is ...
P = 8D +40
_____
The page count is the product of the pages per day and the number of days. Since Carly started with a page count of 40, that is added to the product.
Ans5
Step-by-step explanation:
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