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mojhsa [17]
3 years ago
10

Write an equation of the line that has a slope of 5 and goes through the point (3,3)

Mathematics
1 answer:
professor190 [17]3 years ago
8 0

Answer:

y=5x-12

Step-by-step explanation:

The general equation of a line is <em>y=mx+b</em>.

The equation you currently have is <em>y=5x+b</em>.

Plug in the point (3,3) which will get you <em>3=5(3)+b</em>.

Solve the equation by solving what the y-intercept (b) is to create the new final equation.

3=5(3)+b

3=15+b

b=3-15

b=-12

y=5x-12

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Help please and thank you!!!
Ghella [55]

Answer:

The slop is undifined cause ur basicly just falling cause theirs no x just straight down forever


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3 years ago
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(Brainliest) Find the equation of the graph, at what values of x does the graph reach its maximum values, on what intervals is t
Gnom [1K]

Answer:

Step-by-step explanation:

The max value that this function reaches is 6, and the function reaches this value repeatedly, beginning at x = 0 and then at x = 6, 12, 15, etc.  This tells us that the period of the function is 6.  

The function is increasing on (3, 6), (9, 12), and so on

The function is even because the graph is symmetrical about the y-axis.

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3 years ago
Given g(x)=5x+2, find g(-6)
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What is the slope of the line that passes through the points (8,2) and (10,2)? Write your answer in the simplest form.​
Oxana [17]

slope of line=(y2-y1)/(x2-x1)

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(x1,y1)=(8,2)

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answer

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3 0
2 years ago
What is 9/10 + 7/15
Yakvenalex [24]

\huge\text{Hey there!}

\mathsf{\dfrac{9}{10}+\dfrac{7}{15}}

\large\textsf{FIRST: FIND the LCD (Lowest Common Denominator) then solve}\\\large\textsf{from there!}

\large\textsf{If you have calculated it correctly, you should have came up with \underline{\bf 30}}\\\large\textsf{as your LCD (Lowest Common Denominator).}

\mathsf{= \dfrac{9\times3}{10\times3}+ \dfrac{7\times2}{15\times2}}

\mathsf{9\times3=\bf 27}\\\mathsf{10\times3=\bf 30}\\\\\mathsf{7\times2=\bf 14}\\\mathsf{15\times2=\bf 30}

\mathsf{= \dfrac{27}{30}+\dfrac{14}{30}}

\mathsf{= \dfrac{27+14}{30}}

\mathsf{27+ 14=\bf 41}\\\\\mathsf{30+0=\bf 30}

\mathsf{= \dfrac{41}{30}}\large\textsf{ which you could convert to }\mathsf{1 \dfrac{11}{30}}

\boxed{\boxed{\large\textsf{ANSWER: }\bf \dfrac{41}{30} \large\textsf{ or }\mathsf{\bf 1 \dfrac{11}{30}\large\textsf{ because they both equal the same thing}}}}}\huge\checkmark

\large\text{Good luck on your assignment and enjoy your day!}

~\frak{Amphitrite1040:)}

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2 years ago
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