- The margin of error of the proportion given is of 2.9%.
- Applying the margin of error, the confidence interval is (29.1%, 34.9%).
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The margin of error of a confidence interval of a proportion
in a sample of size n, with a confidence level of
, is:

In which z is the z-score that has a p-value of
.
The confidence interval is:

In this problem:
- Poll of 1012 people, thus
. - 32% keep a dog, thus

95% confidence level
Thus
, z is the z-score that has a p-value of
, so
.
The margin of error is:

As a percent, 2.9%, as 0.029 x 100% = 2.9%.
Now for the confidence interval, which is <u>percentage plus/minus margin of error</u>, thus:


The confidence interval is (29.1%, 34.9%).
A similar problem is given at brainly.com/question/16807970
Answer:
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1,963
Step-by-step explanation:
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Composite is a number that is NOT prime. So we want to find an odd perfect square that IS prime to be a counterexample.
√36 = Not odd
√49 = 7 Factors only 1 * 7 so it is prime
√81 = 9 Factors 1, 3, 9 composite
√225 = 15 Factors 1,3, 5,9,15, 25, 45, 75, 225 composite
Counterexample for 2∧n - 1 Is prime
2^6 - 1 = 64 - 1 = 63 NOT PRIME Factors are: 1, 3, 7, 9,21, 63
2^5 - 1 = 32 - 1 = 31 Prime
2^3 - 1 = 8 - 1 = 7 Prime
2^2 - 1 = 4 - 1 = 3 Prime