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sesenic [268]
3 years ago
5

Please help with question 5!! BRAINLIEST to correct answer!

Mathematics
1 answer:
REY [17]3 years ago
3 0
I’d go with A

kabiwbhej
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The center of a circle lies on _____.
algol [13]
<h2>Answer:</h2>

A) every diameter

<em>The center of a circle lies on </em><em>every diameter.</em>

<h2>Explanation:</h2>

B) The circle: A circle is a two-dimensional shape where all points are the same distance from the center. So this definition doesn't match the definition of the center of the circle. The center is just a point not several ones.

C) A tangent line: obviously this definition is false. A tangent line is a line not a point.

D) Every chord: A chord is any line segment between two points on a circle. The only chord that passes through is the diameter. So this definition does not include all the chords of a circle

A) Every diameter: This is the correct option! A diameter is any chord that <em>passes through the center</em>.

4 0
4 years ago
Plase dont awnser just for points
egoroff_w [7]
So 3 2/3 is about 3.67 so it would go in between 3.65 and 3.7. So it would be the second answer.
5 0
4 years ago
Read 2 more answers
A table saw is on clearance for 20% off. If the sale price of the table saw is $380, what was the original price? Justify your s
Nikolay [14]

20% off means it is selling for 80% of the original price ( 100% - 20% =80%)

Divide the sale price by 80% as a decimal:

380/0.80 = 475

The original price was $475

Justify:

Multiply the original price by 20% and subtract:

475 x 0.20 = 95

475-95 = $380 which is the sale price.

5 0
3 years ago
Read 2 more answers
How do I verify #15 using fundamental trig identities?
expeople1 [14]

We start with the more complicated side which is the left side, and show that, on using some trigonometric identities, we will get the term on the right side .

\frac{sin \theta + tan \theta}{1+cos \theta}

Using Quotient identity for tangent function, we will get

\frac{sin \theta+ \frac{sin \theta}{cos \theta}}{1+cos \theta}

\frac{sin \theta cos \theta + sin \theta}{cos \theta(1+cos \theta)}

Taking out sine function from the numerator

=\frac{sin \theta(1+cos \theta)}{cos \theta(1+cos \theta)}

Cancelling the common term of numerator and denominator

=\frac{sin \theta}{cos \theta} = tan \theta

7 0
3 years ago
It’s about solving systems of equations does anyone know the answer please
Rasek [7]

Answer:

A

Step-by-step explanation:

One Solution

6 0
3 years ago
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