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3 years ago

12

HELP!!!!

1 answer:

vichka [17]3 years ago

3 0

Her distance is increasing fastest from minute 5 to 6 as the rate of change of the distance in that interval (40 mph increase) is greater than that if any other interval

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Carol is baking cookies and needs 2 1/4 cups of flour 2/3 cup of white sugar 1/4 cup of brown sugar and 1/16 cup of baking soda

andre [41]

1) Amount of white sugar ÷ the amount of brown sugar =

$\frac{2}{3}$ ÷ $\frac{1}{4}$

= $\frac{2}{3}.\frac{4}{1}= \frac{8}{3}=2\frac{2}{3}.$

2)Amount of white sugar after increase =

$\frac{2}{3}+2\frac{1}{2}=\frac{2}{3}+\frac{5}{2}=\frac{19}{6}=3\frac{1}{6}.$

3)Amount of flour after increase= $2\frac{1}{4}+2\frac{1}{2}=\frac{9}{4}+\frac{5}{2}=\frac{19}{4}=4\frac{3}{4}.$

4) Amount of brown sugar =

$\frac{1}{4}$ cup. $\frac{1}{4}of\frac{1}{4}=\frac{1}{16}$

$\frac{1}{16}$ cup was used .

5)Amount of Baking soda used=

$\frac{1}{4}of\frac{1}{16}=\frac{1}{64}$

7 0

3 years ago

Write the difference as a mixed number.<br>3- 1 1/3<br><br>

BigorU [14]

Answer:

11/3 as a mixed number would be 3 2/3

Step-by-step explanation:

6 0

3 years ago

(-8x-6)-4^2 evaluate

omeli [17]

answer:

-8x-22

step by step explanation:

none

7 0

3 years ago

Read 2 more answers

1. Maria has 5 yards of fabric. A scarf uses 13 of a

kogti [31]

How is she starting off with five yards of fabric but is using 13 and 72 yards of fabric something isn’t right with this question...

6 0

3 years ago

If 180° < α < 270°, cos⁡ α = −817, 270° < β < 360°, and sin⁡ β = −45, what is cos⁡ (α + β)?

eduard

Answer:

$cos(\alpha+\beta)=-\frac{84}{85}$

Step-by-step explanation:

we know that

$cos(\alpha+\beta)=cos(\alpha)*cos(\beta)-sin(\alpha)*sin(\beta)$

Remember the identity

$cos^{2} (x)+sin^2(x)=1$

step 1

Find the value of $sin(\alpha)$

we have that

The angle alpha lie on the III Quadrant

so

The values of sine and cosine are negative

$cos(\alpha)=-\frac{8}{17}$

Find the value of sine

$cos^{2} (\alpha)+sin^2(\alpha)=1$

substitute

$(-\frac{8}{17})^{2}+sin^2(\alpha)=1$

$sin^2(\alpha)=1-\frac{64}{289}$

$sin^2(\alpha)=\frac{225}{289}$

$sin(\alpha)=-\frac{15}{17}$

step 2

Find the value of $cos(\beta)$

we have that

The angle beta lie on the IV Quadrant

so

The value of the cosine is positive and the value of the sine is negative

$sin(\beta)=-\frac{4}{5}$

Find the value of cosine

$cos^{2} (\beta)+sin^2(\beta)=1$

substitute

$(-\frac{4}{5})^{2}+cos^2(\beta)=1$

$cos^2(\beta)=1-\frac{16}{25}$

$cos^2(\beta)=\frac{9}{25}$

$cos(\beta)=\frac{3}{5}$

step 3

Find cos⁡ (α + β)

$cos(\alpha+\beta)=cos(\alpha)*cos(\beta)-sin(\alpha)*sin(\beta)$

we have

$cos(\alpha)=-\frac{8}{17}$

$sin(\alpha)=-\frac{15}{17}$

$sin(\beta)=-\frac{4}{5}$

$cos(\beta)=\frac{3}{5}$

substitute

$cos(\alpha+\beta)=-\frac{8}{17}*\frac{3}{5}-(-\frac{15}{17})*(-\frac{4}{5})$

$cos(\alpha+\beta)=-\frac{24}{85}-\frac{60}{85}$

$cos(\alpha+\beta)=-\frac{84}{85}$

4 0

3 years ago