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vovikov84 [41]
3 years ago
5

Find the volume of a hemisphere with a radius of 8. Round to the nearest tenth.

Mathematics
1 answer:
skad [1K]3 years ago
6 0

Answer:

V(hemisphere) = 1072.3in^3

Step-by-step explanation:

To find the volume of a hemisphere, we will have to take the volume of a sphere as a whole and divide it by 2. This is because a hemisphere is half of a sphere.

The volume of a sphere is:

Let's plug in the radium of 8 into the equation and solve:

Now, divide it by 2

V(sphere) = (2144.660585)/2

V(hemisphere) = 1072.3in^3

I hope this helps!!

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Your cellphone plan is by the minute . Each minute of use costs $0.10 . Create a relation that represents the amount spent ,A, p
d1i1m1o1n [39]

Answer:

Talking 65 minutes, $ 6.50 must be paid.  

Step-by-step explanation:

Since your cell phone plan is by the minute, and each minute of use cost $ 0.10, to create a relation that represents the amount spent, A, per minute, m, of call time, and then use the relation to find the amount spent if you talk 65 minutes, the following calculations must be performed:

0.10 x M = A

0.10 x 65 = A

6.50 = A

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3 years ago
Can som help plzzzzzzz
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3 years ago
Squash and Water are mixed in the ratio 1:5. Marion needs to make cups of juice that are 150ml for a party. She anticipates she
PIT_PIT [208]
You need to add 1 and 5 and get 6
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6 0
3 years ago
How do you write 5.44 in words?
wel

Answer:

five and forty-four hundredths

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Solve 2x^2+x-4=0<br> X^2+_×+_=0
natima [27]

Answer:

Hopes it helps

Step-by-step explanation:

The Quadratic Polynomial is

2 x² +x -4=0

Using the Determinant method to find the roots of this equation

For, the Quadratic equation , ax²+ b x+c=0

(b) x²+x=0

x × (x+1)=0

x=0  ∧ x+1=0

x=0     ∧   x= -1

You can look the problem in other way

the two Quadratic polynomials are

2 x²+x-4=0, ∧ x²+x=0

x²= -x

So, 2 x²+x-4=0,

→ -2 x+x-4=0

→ -x -4=0

→x= -4

∨

x² +x² +x-4=0

x²+0-4=0→→x²+x=0

→x²=4

x=√4

x=2 ∧ x=-2

As, you will put these values into the equation, you will find that these values does not satisfy both the equations.

So, there is no solution.

You can solve these two equation graphically also.

3 0
3 years ago
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