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vovikov84 [41]
3 years ago
5

Find the volume of a hemisphere with a radius of 8. Round to the nearest tenth.

Mathematics
1 answer:
skad [1K]3 years ago
6 0

Answer:

V(hemisphere) = 1072.3in^3

Step-by-step explanation:

To find the volume of a hemisphere, we will have to take the volume of a sphere as a whole and divide it by 2. This is because a hemisphere is half of a sphere.

The volume of a sphere is:

Let's plug in the radium of 8 into the equation and solve:

Now, divide it by 2

V(sphere) = (2144.660585)/2

V(hemisphere) = 1072.3in^3

I hope this helps!!

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Which list orders the numbers from least to greatest
DENIUS [597]
The second line
least to greatest: -3, -2.4, -21/4, -1.5, -11/8
5 0
3 years ago
During a basketball practice, Mai attempted 49 free throws and was on 25% of them. How many successful free throws did she make?
Brrunno [24]

Mai made 12 successful free throws.

Step-by-step explanation:

Given,

Free throws made by Mai = 49 free throw

Successful throws = 25%

Number of successful throws = 25% of free throws

Number of successful throws = \frac{25}{100}*49

Number of successful throws = \frac{1225}{100} = 12.25

Rounding off to nearest whole number;

Number of successful throws = 12

Mai made 12 successful free throws.

Keywords: percentage, division

Learn more about division at:

  • brainly.com/question/11150876
  • brainly.com/question/11175936

#LearnwithBrainly

6 0
4 years ago
If the period of a sine function is the number of units before the cycle begins to repeat, why would the period of the regressio
Jlenok [28]

Answer:

This means that after going around the unit circle once (2π radians), both functions repeat. So the period of both sine and cosine is 2π . Hence, we can find the whole number line wrapped around the unit circle.

Step-by-step explanation:

5 0
3 years ago
Given sinθ=- 3/5 and cscθ=-5/3 in quadrant III, find the value of other trigonometric functions using a Pythagorean Identity. Sh
Yakvenalex [24]
Let ABC be a triangle in the 3rd quadrant, right-angled at B. 
 So, AB-> Perpendicular BC -> Base AC -> Hypotenuse. 
Given: sinθ=-3/5 cosecθ=-5/3 
 According to Pythagorean theorem, square of the hypotenuse is equal to the sum of square of the other two sides.
 Therefore in triangle ABC, 〖AC〗^2=〖AB〗^2+〖BC〗^2 ------
--(1)
 Since sinθ=Perpendicular/Hypotenuse ,
 AC=5 and AB=3
 Substituting these values in equation (1)
 
〖BC〗^2=〖AC〗^2-〖AB〗^2

 ă€–BC〗^2=5^2-3^2
 

 ă€–BC〗^2=25-9

 ă€–BC〗^2=16

 BC=4 units

 Since the triangle is in the 3rd quadrant, all trigonometric ratios, except tan
and cot are negative.
 So,cosθ=Base/Hypotenuse Cosθ=-4/5 
 secθ=Hypotnuse/Base secθ=-5/4 
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 cotθ=Base/Perpendicular cotθ=4/3
4 0
3 years ago
Fill in the missing reason in proof.
KiRa [710]

Answer:

  • SAS

Step-by-step explanation:

<u>As per steps given the congruent pairs are:</u>

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  • BD and CD
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So two sides and included angle - it represents side-angle-side or SAS congruency theorem

8 0
3 years ago
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