Question

Which are the solutions of he quadratic equation ? x2 = 9x + 6

Answer 1

Answer:

$x=\frac{9\pm \sqrt{105}}{2}$

Step-by-step explanation:

We have been given a quadratic equation $x^2=9x+6$. We are asked to find the solutions of our given equation.

First of all, we will gather all terms on one side of equation as:

$x^2-9x-6=9x-9x+6-6$

$x^2-9x-6=0$

Now, we will use quadratic formula to solve for x as:

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$x=\frac{-(-9)\pm \sqrt{(-9)^2-4(1)(-6)}}{2(1)}$

$x=\frac{9\pm \sqrt{81+24}}{2}$

$x=\frac{9\pm \sqrt{105}}{2}$

Therefore, the solutions of our given equation are $x=\frac{9\pm \sqrt{105}}{2}$.

Answer 2

Put everything on the same side of the equals sign and set it equal to zero so you can factor it.  $x^{2} -9x-6=0$.  In order to factor that you have no choice really but to put it into the quadratic formula.  When you do that you find that your zeros are x = 9.623475383 and -.623475383