An analyst at a paper company made the table below of the sales by month at his company.
2 answers:
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Given:
The parent function is:
This function shift 1 unit left, vertically stretch by a factor of 3 and reflected over the x-axis.
To find:
The function after the given transformations.
Step-by-step explanation:
The transformation is defined as
... (i)
Where, k is stretch factor, a is horizontal shift and b is vertical shift.
If k<0, then the graph of f(x) is reflected over the x-axis.
If 0<|k|<1, then the graph compressed vertically by factor |k| and if |k|>1, then the graph stretch vertically by factor |k|.
If a>0, then the graph shifts a units left and if a<0, then the graph shifts a units right.
If b>0, then the graph shifts b units up and if b<0, then the graph shifts b units down.
It is given that the graph of f(x) shifts 1 unit left, so a=1.
The graph of f(x) vertically stretch by a factor of 3, so |k|=3.
The graph of f(x) reflected over the x-axis, so k=-3.
There is no vertical shift, so b=0.
Putting in (i), we get
Therefore, the correct option is B.
Answer:
D
Step-by-step explanation:
Given that the segment is an angle bisector then the ratio of sides and base are equal, that is
=
( cross- multiply )
10x = 72 ( divide both sides by 10 )
x = 7.2 → D
Answer:
a. Maximum= 27, minimum= -5
b. Maximum= 19, minimum=-37
Step-by-step explanation:
We have the function . Since the function correspond to a line, then the maximum and minimum values of the function over an interval are in the endpoints of the interval.
Observe that if the line has negative slope then the minimum value is in the right endpoint. If the line has positive slope the minimum value is in the left endpoint of the interval.
The function f(x) has slope m=8. Then
a. the minimum value of f(x) in the interval [0,4] is reach when x=0, and the minimum is and the maximum is
b. the minimum value of f(x) in the interval [-4,,3] is reach when x=-4, and the minimum is and the maximum is