Can someone help me find the missing side length!

Mathematics

2 answers:

aev [14]3 years ago

6 0

Answer:

Step-by-step explanation

so what I did is I divided 15 by 5 to get 3 also 9 divided by 3 equals 3 to so you could of also done that.

then i multiplied to 4 x 3 to get the missing side length which equals 12

pashok25 [27]3 years ago

5 0

Answer:

the answer is 12

Step-by-step explanation:

to find the length we us this formula a²+b²=c²

a²+b²=c²

a²+(9)²=(15)²

a²+81=225

a²=225-81

a²=144

a=√144

a= 12 unit

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Answer:

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Step-by-step explanation:

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The graph below shows the value of Edna's profits f(t), in dollars, after t months:

umka21 [38]

Since we know that the graph of our quadratic function has x-intercepts at (6,0) and (18,0), $x=6$ and $x=18$ are the zeroes of our quadratic. To find our quadratic we are going to factor each zero backwards and multiply them:
$x=6$
$x-6=0$
$x=18$
$x-18=0$

$(x-6)(x-18)=x^{2}-6x-18x+108$
$=x^{2}-24x+108$

Now that we have our quadratic function, we are going to use the average formula: $m= \frac{f(9)-f(3)}{9-3}$
$where$
$f(9)$ is the function evaluated at the 9th month
 $f(3)$ is the function evaluated at the 3rd month

$m= \frac{f(9)-f(3)}{9-3}$
$m= \frac{[9^{2}-24(9)+108]-[3^{2}-24(3)+108]}{9-3}$
$m= \frac{-27-45}{6}$
$m= \frac{-72}{6}$
$m=-12$

We can conclude that the closest approximate average rate of change for Edna's profits from the 3rd month to the 9th month is: B. −11.63 dollars per month.