<span>speed = distance/time
total time is 8 hours
outgoing speed is 160 km per hour,
so time = d/160
</span><span>returning speed is 240 km per hour,
so time = d/240
d/160 + d/240 = 8
3d/480 + 2d/480 = 8
5d/480 = 8
5d =480 (8)
5d = 3840
d=3840/5
d=768
answer: so the distance is 768 km</span>
Answer:
9 cm
Step-by-step explanation:
The formula to calculate the area of a triangle is: A = bXh square units.
Therefore simply divide the area given 54 cm over base 6 cm to get the height. 54÷ 6 = 9
Hope this suffices.
The cost of fencing the path is Rs 1539.38.
It is required to find the cost of fencing the path.
<h3>
What is circle?</h3>
A circle is a closed two-dimensional figure in which the set of all the points in the plane is equidistant from a given point called “centre”. The perimeter around the circle is known as the circumference.
Given that:
radius of a circular path is 7m.
Rate = Rs .35 per meter
We know that
Circumference of circle =

Circumference of circle=43.98 m
Now,
Cost = Circumference × Rate
Cost =43.98× 35
Cost = Rs 1539.38
Therefore, the cost of fencing the path is Rs 1539.38.
Learn more about circle here:
brainly.com/question/11833983
#SPJ1
For
problem number 3, the answer is (3, 5). The correct answer between all
the choices given is the second choice or letter B.
For
problem number 5, the answer is median. The correct answer between all
the choices given is the third choice or letter C.
I am hoping that these answers
have satisfied your queries and it will be able to help you, and if you’d like,
feel free to ask another question.
It's evident that the first four terms are 4, 4/3, 4/9, and 4/27. So the fourth partial sum of the series is

It's as easy as adding up the fractions, but I bet this is supposed to be an exercise in taking advantage of the fact that the series is geometric and use the well-known formula for computing such a sum.
Multiply the sum by 1/3 and you have

Now subtracting this from

gives

That is, all the matching terms will cancel. Now solving for

, you
have

