<em><u>Question:</u></em>
Consider the following equation: f(x)=x^2+4\4x^2-4x-8 name the vertical asymptote(s)
<em><u>Answer:</u></em>
The vertical asymptotes are x = 2 or x = -1
<em><u>Solution:</u></em>
Given that,
For vertical asymptotes, set the denominator to zero and then solve the quadratic equation
Thus the vertical asymptotes are x = - 1 and x = 2
12) the radius is 15 so with the equation (3.14)*r^2, we get (3.14)(15^2)=706.5
13) true, true (if x=4), true
14) y=0.75x+4.50, $8.25
Answer:
7
Step-by-step explanation:
The surface area is the lateral area plus the base area. The base area is 9*5=45. Since there are two bases, its 90. Subtract that from 286 to get the lateral surface area, which is 196. The lateral surface area is the base perimeter*height. The base perimeter is 9+9+5+5= 28. 196/28=height. The height is 7
I think is 2x+y=-5 the answer
Answer:
Step-by-step explanation:
if you know 50*4=200, you must also know that 50*10=500 and that 4*100=400 so 500*400= 50*10*4*100
multiplication is comutative so
50*4*10*100=200*1,000= 200, 000
