Where is 2/4 on the number line with a number line of on 3 ticks?

PLS ANSWEE THIS AND IF YOU DO THANK YOU!!!

Anna71 [15]

Answer:

$9.50

Step-by-step explanation:

i am 100% sure

3 0

3 years ago

The table shows the number of minutes Garrett practiced his trombone each week in one month. Week Number of Minutes Practiced 1

vredina [299]

Answer:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

The reason is because we assume that each week have the same weight and replacing we got:

$\bar X= \frac{190+163+327+205}{4}= 221.25$

And the best option would be:

D. 221.25

Step-by-step explanation:

For this case we have the following data given

Week 1 2 3 4

Minutes 190 163 327 205

For this case we can find the mean with the following formula:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

The reason is because we assume that each week have the same weight and replacing we got:

$\bar X= \frac{190+163+327+205}{4}= 221.25$

And the best option would be:

D. 221.25

4 0

3 years ago

Y-x=15 y-x=5 using elimination

Galina-37 [17]

Answer:

No solution

Step-by-step explanation:

To eliminate is to get rid of one of the variables.

You can choose to either add each term in the equations or subtract each term in the equation.

For a variable to be eliminated, there must one pair that have the same constant with it. Each equation already has the same constant with a variable.

Try adding them.

. y - x = 15

+ y - x = 5

2y - 2x = 20 No variables were eliminated.

Try subtracting.

. y - x = 15

- y - x = 5

0y - 0x = 10 All variables were eliminated.

. 0 = 10 This is false.

This system of equations cannot be solved.

Graphically, these two lines would have the same slope and are parallel. The solution to a system is same as the point of intersection. Parallel lines never meet, never intersect, therefore there is no solution.

3 0

3 years ago

You throw a ball up and its height h can be tracked using the equation h=2x^2-12x+20.

postnew [5]

This problem seems to be wrong because no minimum point was found and no point of landing exists

Answer:

1) There is no maximum height

2) The ball will never land

Step-by-step explanation:

Derivatives

Sometimes we need to find the maximum or minimum value of a function in a given interval. The derivative is a very handy tool for this task. We only have to compute the first derivative f' and have it equal to 0. That will give us the critical points.

Then, compute the second derivative f'' and evaluate the critical points in there. The criteria establish that

If f''(a) is positive, then x=a is a minimum

If f''(a) is negative, then x=a is a maximum

1)

The function provided in the question is

$h(x)=2x^2-12x+20$

Let's find the first derivative

$h'(x)=4x-12$

solving h'=0:

$4x-12=0$

x=3

Computing h''

h''(x)=4

It means that no matter the value of x, the second derivative is always positive, so x=3 is a minimum. The function doesn't have a local maximum or the ball will never reach a maximum height

2)

To find when will the ball land, we set h=0

$2x^2-12x+20=0$