4. Jake has m nails and twice as many bolts as nails. He buys another 20 nails and 30 bolts.

No links and no false answers please help i'll mark you the brainlest

nadezda [96]

If you look at the line it never stops. Y can be any number and X can be any number so X and y are elements of reels meaning your answer is a

8 0

2 years ago

<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7By%7D%7B2%7D%20%20%3C%20%20-%203" id="TexFormula1" title=" \frac{y}{2} < - 3"

Allisa [31]

Hey!

Okay, to solve this problem, we'd first have to multiply both sides by two. The reason we do this is to get $y$ on its own.

Original Equation : 
$\frac{y}{2}$ < $-3$

New Equation {Changed by Multiplying 2 on Both Sides} :
$\frac{2y}{2}$ < $2$ ( $-3$ )

And we simplify the equation to get our answer.

Old Equation :
$\frac{2y}{2}$ < $2$ ( $-3$ )

New Equation {Changed by Simplification} :
y < -6

So, the equation $\frac{y}{2}$ < -3 simplified is y < -6.

Hope this helps!

- Lindsey Frazier ♥

8 0

2 years ago

What’s 8x8 This is to test how the app works not serious

lisov135 [29]

Answer:

64

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Priya will graph a line with the equation y = 3 4x - 4. She wants to know what the line will look like before she graphs the lin

Natalija [7]

yes yes very very good my boy

4 0

2 years ago

true or false If x represents a random variable with mean 114 and standard deviation 40, then the standard deviation of the samp

Goshia [24]

Answer:

$\mu = 114, \sigma = 40$

We also know that we select a sample size of n =100 and on this case since the sample size is higher than 30 we can apply the central limit theorem and the distribution for the sample mean would be given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard deviation for the sampling distribution would be:

$\sigma_{\bar X}= \frac{40}{\sqrt{100}}= 4$

So then the answer is TRUE

Step-by-step explanation:

Let X the random variable of interest and we know that the true mean and deviation for this case are given by:

$\mu = 114, \sigma = 40$

We also know that we select a sample size of n =100 and on this case since the sample size is higher than 30 we can apply the central limit theorem and the distribution for the sample mean would be given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard deviation for the sampling distribution would be:

$\sigma_{\bar X}= \frac{40}{\sqrt{100}}= 4$

So then the answer is TRUE

6 0

3 years ago