(81^-0.25)^3 = ( 1 / (81^0.25) )^3
<span>81^.025 is the 4th root of 81 which is 3 </span>
<span>Therefor </span>
<span>( 1 / (81^0.25) )^3 = (1/3)^3 </span>
<span>(1/3)^3 = 1/27 <-----
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Answer:
QR(3), RS(3), PQ(3), ST(11), RP(6), RT(14), SP(9), QT(17)
Step-by-step explanation:
The diagram is not shown, but we assume the points are in the sequence ...
P, Q, R, S, T
Since QR = RS, R is apparently the midpoint of QS, So ...
23. QR = 6/2 = 3
24. RS = QR = 3
25. PQ = QR = 3
26. ST = PT -PQ -QS = 20 -3 -6 = 11
27. RP = PQ +QR = 3 +3 = 6
28. RT = RS +ST = 3 +11 = 14
29. SP = PQ +QS = 3 +6 = 9
30. QT = QS +ST = 6 +11 = 17
Answer:
a10 = 12/7
Step-by-step explanation:
an = a1 + (n-1) d
a10 = 3/7 + ( 10-1) 1/7
a10 = 3/7 + (9) 1/7
a10 = 3/7 + 9/7
a10 = 12/7
Answer:
11
Step-by-step explanation:
3+7=10
4/8=1/2
12+1/2=1
10+1=11
Answer:Solve equations by clearing the Denominators Find the least common denominator of all the fractions in the equation. Multiply both sides of the equation by that LCD. This clears the fractions.
Step-by-step explanation:Solve equations by clearing the Denominators Find the least common denominator of all the fractions in the equation. Multiply both sides of the equation by that LCD. This clears the fractions.
