Помогите стоянок пожалуйста

Someone please help me thank you

Elis [28]

Answer:

x intercept 2

y intercept 1

Step-by-step explanation:

The x intercept is where it crosses the x axis( or horizontal axis) It crosses at x =2

The y intercept is where it crosses the y axis ( or vertical axis). It crosses at y =1

4 0

3 years ago

What are the coordinates of the midpoint of the line segment with endpoints 2,5 and 4,-7

Phoenix [80]

<h3>Answer: (3, -1)</h3>

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Explanation:

The midpoint formula is $(x_m, y_m) = \left(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\right)$

This basically says to add the corresponding coordinates and divide by 2.

The given points (2,5) and (4,-7) have x coordinates of 2 and 4. They add to 2+4 = 6, and then that result cuts in half to 6/2 = 3. The x coordinate of the midpoint is 3.

The y coordinate of the midpoint is y = -1 since adding the y coordinates of the given points leads to 5+(-7) = -2 which cuts in half to -1.

So overall the midpoint is located at (3, -1)

8 0

3 years ago

Determine and prove what shape is formed for the given coordinates for ABCD, and then find the

ella [17]

Answer:

Square

Step-by-step explanation:

Plot points A (10,-4), B (6,-7), C (3,-3), D (7,0) on the coordinate plane.

Find slopes of the sides:

$AB:\ \dfrac{-7-(-4)}{6-10}=\dfrac{3}{4}\\ \\BC:\ \dfrac{-3-(-7)}{3-6}=-\dfrac{4}{3}\\ \\CD:\ \dfrac{0-(-3)}{7-3}=\dfrac{3}{4}\\ \\DA:\ \dfrac{-4-0}{10-7}=-\dfrac{4}{3}$

The slopes of opposite sides are the same, so opposite sides are parallel. The slopes of adjacent sides have product of -1, then adjacent sides are perpendicular.

Find the lengths of all sides:

$AB=\sqrt{(10-6)^2+(-4-(-7))^2}=\sqrt{4^2+3^2}=\sqrt{16+9}=\sqrt{25}=5\ units\\ \\BC=\sqrt{(6-3)^2+(-7-(-3))^2}=\sqrt{3^2+4^2}=\sqrt{16+9}=\sqrt{25}=5\ units\\ \\CD=\sqrt{(3-7)^2+(-3-0)^2}=\sqrt{4^2+3^2}=\sqrt{16+9}=\sqrt{25}=5\ units\\ \\AD=\sqrt{(10-7)^2+(-4-0)^2}=\sqrt{3^2+4^2}=\sqrt{16+9}=\sqrt{25}=5\ units\\ \\$

All four sides are of the same length.

Quadrilateral ABCD is a square (all sides of equal length and perpendicular)

4 0

3 years ago

Drag the tiles to the correct boxes to complete the pairs.

kvasek [131]

The value of x for each radical equation is 243 , 125,8,256 respectively.

The correct question is attached as an image with the answer.

<h3>What is a Radical Equation ?</h3>

When in an equation the variable is under a radical it is called a Radical Equation.

It is given in the question that

which radical matches to the solution

$\rm \sqrt[5]{x^4} = 81 \\\\\sqrt[3]{x^4} = 625\\\\\sqrt[3]{x^5} = 32\\\\ \sqrt[4]{x^3}=64$

$\rm x^4 = 81^5\\x = 243$

$\rm x^4 = 625^3\\x = 125\\$

$x^5 = 32^3\\x = 8\\$

$\rm x ^3 = 64^4\\x = 256$

Therefore for each radical the value of x is determined.

To know more about Radical Equation

brainly.com/question/8606917

#SPJ1

4 0

2 years ago

I NEED HELP!!!

Ierofanga [76]

Standard equation for a circle is: (x -h)² + (y - k)² = r²
(h,k) is the center which is given to be: (0,0) so you just need the radius.
The radius is the distance from the center to the point (-4,5) on the edge.

Use the distance formula

d = √[(-4 - 0)² + (5 -0)²]
d = √[16 + 25]
d = √[41]

radius is √[41]
so the equation for the circle is: x² + y² = 41

7 0

3 years ago