Answer:
With a skewed distribution and data with outliers.
Step-by-step explanation:
There are three measures of central tendency.
- Mean: It is the average value of data and affected by presence of outliers.
- Median: It is the value that divides the data into two equal parts. It is a position based measure of tendency.
- Mode: It is the most frequent observation in the data.
- For a symmetrical distribution for continuous data, the mean, median, and mode are equal.
- For such case mean is a better measure of central tendency because it includes all of the data in the calculations.
- Median is the best measure of central tendency when the data is not symmetrical because the median is position based.
- Advantage of the median:
The median is not affected by outliers and skewed data as compared to the mean.
Thus, median likely to produce a better measure of central tendency than the mean with a skewed distribution and data with outliers.
Answer:
2.33333333
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given that,
- p ( probability that the child has disease) = 25% = 0.25
- n = number of children = 3
The probability mass function of binomial distribution is,
- (P = X) = (nCx) X (p)^x X (1 - p)^n-x ; x = 0, 1, 2 ,3
- = 3Cx X (0.25)^x X (1 - 0.25)^3-x ; ( n = 3, p = 0.25
a) P ( two will have disease)
p ( X = 2) = 3C2 X (0.250^2 X (1 - 0.25) ^3-2
= 0.1406
b) P ( none will have disease)
p (X = 0) = 3C0 X (0.25)^0 X (1 - 0.25)^3-0
= 0.4219
c) P (neither having the disease nor being a carrier) = 25% = 0.25
The probability that at least one will neither having the disease nor being a carrier ;
P(X> or equals to) = 1 - P(X < 1)
= 1 - P( X = 0)
= 1 - 3C0 X (0.25)^0 X (1 - 0.25)^3-0
= 0.5781
d) p( the first child with the disease will the be 3rd child)
P(X = x) = (1-p)^x-1 X p
p( X= x) = ( 1 - 0.25 )^x -1 X 0.25
for third child = P(X = 3) = (1 - 0.25)^3-1 X (0.25)
= 0.1406
Answer:
Step-by-step explanation:
Yup its correct :)