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Ierofanga [76]
3 years ago
8

In isosceles AEFG shown to the right, EG=EF=10=and GF=12 12. If an altitude was drawn from point E to overline GF what would be

its length? Show how you arrived at your answer.
Mathematics
1 answer:
Dovator [93]3 years ago
5 0
You will need to use GCF 12 equals 11 altitude
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F(x)= x/x-7<br> What is the domain of f?
Dmitry [639]

Answer:

(-∞,7) U (7,∞)

Step-by-step explanation:

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3 years ago
I’m trying to correct this problem but I don’t know how can someone help me
BartSMP [9]

Remark

It is not a straight line distance from the park to the mall. None of the answers give you that result. And if you know what displacement is, none of the answers are really displacement either. The distance is sort of a "as the crow flies." distance. There's a stop off in the middle of town.

Method

You need to use the Pythagorean Formula twice -- once from the park to the city Center and once from the city center to the mall.

Distance from the Park to the city center.

a = 3   [distance east]

b = 4  [distance south]

c = ??

c^2 = 3^2 + 4^2        Take the square root of both sides.

c = sqrt(3^2 + 4^2)

c = sqrt(9 + 16)          Add

c = sqrt(25)

c = 5

So the distance from the park to the city center is 5 miles

Distance from City center to the mall

a = 2 miles [distance east]

b = 2 miles [distance north]

c = ??

c^2 = a^2 + b^2   Substitute

c^2 = 2^2 + 2^2   Expand this.

c^2 = 4 + 4

c^2 = 8             Take the square root of both sides.

sqrt(c^2) = sqrt(8)

c = sqrt(8)          This is the result

c = 2.8

Answer

Total distance = 5 + 2.8 = 7.8

6 0
3 years ago
I need help solving -13&lt;4x+7
arsen [322]

Answer:

the answer is -5< x

Step-by-step explanation:

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5 0
4 years ago
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