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erastova [34]
3 years ago
11

What is the equation of the line which includes points (1, 5) and (-2, -7)?

Mathematics
1 answer:
klasskru [66]3 years ago
5 0
Given two points, the equation of the line can be known by,
                          y - y1 = ((y2 - y1)/(x2 - x1)) (x - x1)
Substituting the known values,
                          y - 5 = ((-7 - 5) / (-2 - 1)) (x - 1) 
The final equation of the line is,
                              y = 4x + 1 
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2/3(x-2)=-2<br>how would I solve this ​
xeze [42]

Answer:

x =(5/3)

Step-by-step explanation:

The given expression is \frac{2}{3(x-2)}  = -2

Now to simplify it,

The first step is to cross multiply.

So, the expression becomes

\frac{2}{(-2)}  = 3(x-2)

or, -1  = 3x - 6

⇒  3x = -1 + 6

⇒ 3x = 5 , or x =(5/3)

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Step-by-step explanation:

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AlladinOne [14]

Answer:

option C

Step-by-step explanation:

option C is the correct answer of this question.

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5 0
2 years ago
Determine the measure of each segment then indicate whether the statements are true or false
kupik [55]

Answer:

d_{AB}\ne d_{JK}

d_{AB}\ne \:d_{GH}

d_{GH}\ne \:d_{JK}

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

Step-by-step explanation:

Considering the graph

Given the vertices of the segment AB

  • A(-4, 4)
  • B(2, 5)

Finding the length of AB using the formula

d_{AB}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

        =\sqrt{\left(2-\left(-4\right)\right)^2+\left(5-4\right)^2}

         =\sqrt{\left(2+4\right)^2+\left(5-4\right)^2}

         =\sqrt{6^2+1}

         =\sqrt{36+1}

        =\sqrt{37}

d_{AB}\:=\sqrt{37}

d_{AB}=6.08 units        

Given the vertices of the segment JK

  • J(2, 2)
  • K(7, 2)

From the graph, it is clear that the length of JK = 5 units

so

d_{JK}=5 units

Given the vertices of the segment GH

  • G(-5, -2)
  • H(-2, -2)

Finding the length of GH using the formula

d_{GH}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

         =\sqrt{\left(-2-\left(-5\right)\right)^2+\left(-2-\left(-2\right)\right)^2}

          =\sqrt{\left(5-2\right)^2+\left(2-2\right)^2}

          =\sqrt{3^2+0}

           =\sqrt{3^2}

\mathrm{Apply\:radical\:rule\:}\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0

d_{GH}\:=\:3 units

Thus, from the calculations, it is clear that:

d_{AB}=6.08  

d_{JK}=5

d_{GH}\:=\:3

Thus,

d_{AB}\ne d_{JK}

d_{AB}\ne \:d_{GH}

d_{GH}\ne \:d_{JK}

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

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Answer:

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Step-by-step explanation:

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