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iVinArrow [24]
3 years ago
7

The cost of two pants and four shirts is $55.85. If a pant costs $7.25 more than a shirt, find the cost of a pant and a shirt. E

stimate to the nearest whole number.
Cost of a shirt is $6 and cost of a pant is $13
Cost of a shirt is $7 and cost of a pant is $14
Cost of a shirt is $8 and cost of a pant is $14
Cost of a shirt is $7 and cost of a pant is $13
Mathematics
2 answers:
Alecsey [184]3 years ago
6 0

Answer:

B

Step-by-step explanation:

muminat3 years ago
4 0
<h2>                   Hey Emma Here<em>!</em></h2>

Answer:

B

Step-by-step explanation:

55.85 divided by 7.25 is 7. something sooooo if pants cost 7 dolars more thats 14

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Carl and rita at breakfast at the local diner. Their bill came to $11.48. They gave their waitress a tip that wad 25% of the bil
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Answer:

(11.48*25%)+11.48


Step-by-step explanation:


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3 years ago
Find the area of the rectangle. Round the answer to the nearest whole number.
Fed [463]

Answer:

The area of the given rectangle is 51

Step-by-step explanation:

First we have to find the coordinates of the vertices of the rectangle.

Then the length and breadth of it using distance formula.

The distance d between points (x₁ , y₁) and (x₂ , y₂) is given by

d= \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}

Finally calculate the area of rectangle using the formula,

Area of rectangle = Length * Breadth

From the given graph, we get the coordinates of the rectangle as

A(2,4) , B(-2,3) , C(1,-9) , D(5,-8)

Breadth, AB = \sqrt{(-2-2)^{2}+(3-4)^{2}} = \sqrt{16+1} = sqrt{17}

Length, BC = \sqrt{(1+2)^{2}+(-9-3)^{2}} = \sqrt{9+144} = 3 sqrt{17}

Now, Area of rectangle = Length * Breadth = AB * BC = √17 * 3√17 = 3 *17 = 51

∴ The area of the given rectangle is 51

7 0
3 years ago
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Given that <img src="https://tex.z-dn.net/?f=I_0%20%3D%2010%5E-12" id="TexFormula1" title="I_0 = 10^-12" alt="I_0 = 10^-12" alig
Alex Ar [27]

The intensity of sound which the decibel level of the sound measures 156 is 3.981 × 10³ W/m²

Decibel level, dB = 10log₁₀(I/I₀) where dB = decibel level = 156, I = intensity at 156 dB and I₀ = 10⁻¹² W/m².

Since we require I, making I subject of the formula, we have

dB/10 = log₁₀(I/I₀)

\frac{I}{I_{0} } = 10^{\frac{dB}{10} } \\I = I_{0} 10^{\frac{dB}{10} }

Substituting the values of the variables into the equation, we have

I = I_{0} 10^{\frac{dB}{10} }\\I = 10^{-12} 10^{\frac{156}{10} }\\I = 10^{-12} 10^{15.6}\\I = 10^{15.6-12} \\I = 10^{3.6} W/m^{2}

I = 3981.072W/m²

I = 3.981 × 10³ W/m²

So, the intensity of sound which the decibel level of the sound measures 156 is 3.981 × 10³ W/m²

Learn more about intensity of sound here:

brainly.com/question/4431819

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3 years ago
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