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Ray Of Light [21]
3 years ago
13

What is the solution of the following system of equations: x = y + 9

Mathematics
1 answer:
mars1129 [50]3 years ago
4 0

Answer:

Answer is (10,1)

Step-by-step explanation:

in photo

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Answer:

Step-by-step explanation:

x + 25 + 4x + 10 = 180

5x + 35 = 180

5x = 145

x = 29

<1 = 29 + 25 = 54

<2= 4(29) + 10 = 116 + 10 = 126

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3 years ago
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soldi70 [24.7K]

Answer:

x = 54°       y = 126°

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Interior angles of a triangle = 180°

Therefore x = 180 - 80 - 46 = 54°

y = 180 - x = 180 - 54 = 126°

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She was at 40 feet below, she swam up getting so she was then at 40-10 = 30 feet below sea level.

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kozerog [31]
The top right is the answer. The base should be square with lengths of 8 and the height is 10.
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3 years ago
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I NEED HELP ASAP, THAK YOU IN ADVANCED
german

1. If Sheryl works 6.5 hours in a day, she makes approximately 85 currency.

2A. If Sherly had not worked for a single hour, she would get no money.

If she worked for 1 hour, here wage would approximately be equal to 13 currency.

If Sheryl works 9 hours she will make approximately 117 currency.

Step-by-step explanation:

Step 1:

To calculate how much Sheryl makes if she works 6.5 hours a day, we check the graph to see what the y value of the graph is when x =6.5.

When x =6.5, the line falls on y = 85.

So if Sheryl works 6.5 hours in a day, she makes approximately 85 currency.

Step 2:

The two points on the graph are at (0, 0) and (1, 13).

This means that if Sherly had not worked for a single hour, she would get no money.

If she worked for 1 hour, here wage would approximately be equal to 13 currency.

These two statements explain the two points on the graph.

Step 3:

To calculate how much Sheryl makes if she works 9 hours, we must create an equation that represents how much money she makes.

If she earns approximately 13 currency an hour, her wage is y = 13x, where x is the number of hours worked and y is the wage.

When x =9, y = 9(13) = 117.

So if Sheryl works 9 hours she will make approximately 117 currency.

5 0
4 years ago
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