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WINSTONCH [101]
1 year ago
7

What values of b satisfy 3(26 + 3)² = 36?

Mathematics
1 answer:
MakcuM [25]1 year ago
7 0

The numeric value of the b is 0.23 which satisfy the given equation.

According to the statement

We have to find that the value of the b.

So, For this purpose, we know that the

The numeric value refers to the worth of each digit depending on where it lies in the number.

From the given information:

The equation is a

3(2b + 3)² = 36

then to find the value of b rearrange the terms then

(2b + 3)² = 12

(2b + 3) =  \sqrt{12}

(2b) =   \sqrt{12}  -3

then

b  = \sqrt{12}  -3/ 2

b = 3.46 - 3/2

b = 0.46/2

b = 0.23.

So, The numeric value of the b is 0.23 which satisfy the given equation.

Learn more about numeric value here

brainly.com/question/24703884

#SPJ9

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Answer:

<u>11,1</u> <u>m/s</u>

Step-by-step explanation:

40km/hr equals 11,1111111 m/s

11,1111111 simplified: <u>11,1</u>

= <u>11,1</u> <u>m/s</u>

5 0
1 year ago
PLEASE HELP NOW ASAP!!!
IceJOKER [234]

She used the associative property which should only be used with positive numbers (sorry if it isn't the answer you're looking for)

3 0
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A toy rocket is launched straight up into the air with an initial velocity of 60 ft/s from a table 3 ft above the ground. If acc
alexdok [17]
The equation is:
h ( t ) = - 16 t² + 60 t + 3
The toy rocket will reach the ground when: h ( t ) = 0
- 16 t² + 60 t + 3 = 0
t _{12} =  \frac{-60+/- \sqrt{3600+192} }{-32}
t 1 = - 0.05
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C ) 3.80 s

3 0
3 years ago
The average estimated hours a person in the United States spent playing video games per year from 2002 to 2012 were 71, 80, 82,
ozzi

Answer:

Population variance 579

Population standard deviation 24

Step-by-step explanation:

The average estimated hours a person in the United States spent playing video games per year from 2002 to 2012 were 71, 80, 82, 78, 80, 91, 107, 121, 125, 131, and 142.

The population variance is given by:

\sigma^2=\frac{\sum(x-\mu)^2}{n}

\mu=\frac{71+80+82+78+80+91+107+121+125+131+142}{11}

\mu=\frac{1108}{11}

This implies that:

\sigma^2=\frac{(71-\frac{1108}{11})^2+(80-\frac{1108}{11})^2+(82-\frac{1108}{11})^2+(78-\frac{1108}{11})^2+(80-\frac{1108}{11})^2+...+(142-\frac{1108}{11})^2}{11}

\sigma^2=\frac{70006}{121} =579 to the nearest whole number

The population standard deviation is

\sigma=\frac{\sqrt{70006} }{11}=24 to the nearest whole number.

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3 years ago
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7nadin3 [17]
If you have 10 boxes and you shade 3 of these boxes, then the fraction of shaded boxes is 3/10.  The fraction of unshaded boxes would just be the remainder of boxes, or 7/10.
7 0
2 years ago
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