4/3 of the area of the larger hexagon to the area of the smaller hexagon
Let the sides of the interior hexagon be 2 cm long, then this hexagon is made up of 6 equilateral triangles of side = 2.
The area of this hexagon = 6 * 1 * sqrt3 = 6 sqrt3 ( as the triangle is made up of 2 60-30-90 triangles)
The exterior hexagon is made up of 6 equilateral triangles with altitude 2 and the area = 6 * 2 * (2 / sqrt3 ) = 24 / sqrt3
area exterior hex / interior hex = 24 / sqrt3 * 1 / 6sqrt3 = 24/18
= 4/3
Required ratio = 4/3 answer
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Answer:
just plug in
g(x)=7x
g(-7)=7*(-7)
7*(-7)=-49
Step-by-step explanation:
Answer:576
Step-by-step explanation:
-8,0,8,...
Common difference=d=8-0
d=8
First term=a=-8
Using the formula
Tn=a + d x (n-1)
T74 = 74th term
T74=-8 + 8 x (74-1)
T74=-8 + 8 x 73
T74=-8 + 584
T74=576
The 74th term=576
Answer:
Step-by-step explanation: