You can use the pythagoras’ theorem and just look at one right triangle.
The dimensions for one of the right triangles is (x/2), 8, and square root of 80.
a^2 + b^c = c^2
when c is the square root of 80.
Plug everything in
(x/2)^2 + 8^2 = (square root of 80)^2
That is equivalent to
((x^2)/4) + 64 = 80
Solve for x
((x^2)/4) = 16
Multiple by 4 on each side
x^2 = 64
Take the square root and you have you’re final answer
x = 8
Answer:
The answer is 246 simplified so A
Step-by-step explanation:
The formula is a^2+b^2=c^2
C is always the hypotenuse so set it up as 4^2+6^2=(3y-2)^2
Option 3 is not possible
-60.2 + 32 = -60.2 + 60
And these are not equal
Rest all options have x and are solvable
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The absolute value of I-44l is 44. Hope this helps!! :) Pls mark me BRAINLIEST!!! :)
