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Iteru [2.4K]
3 years ago
8

How does one solve this?

Mathematics
1 answer:
GuDViN [60]3 years ago
3 0
The answer is a. x>0
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Solve for x: 3 over 3x+ 1 over x+4= 10 over 7x
hram777 [196]

Answer:

3

Step-by-step explanation:

3/3x + 1/x+4 = 10/7x

3/3x + 1/x+4 = 10/7x , x=0,x=-4

1/x + 1/x+4 = 10/7x

1/x + 1/x+4 - 10/7x = 0

7(x+4)+7x-10(x+4) / 7x*(x+4) = 0

7x+28+7x-10x-40 / 7x*(x+4) = 0

4x-12 / 7x*(x+4) = 0

4x-12=0

4x-=12

x=3,x=0,x=-4

x=3

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Step-by-step explanation:

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Step-by-step explanation:

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A square base of a pyramid has the dimensions 5 yards
AfilCa [17]

Answer:

145 yd²

Step-by-step explanation:

There will be dour triangular faces. For a triangle, area is given as

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The surface area of a square base is given by

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Total area will be the sum of triangular and square faces hence 120+25=145 yd²

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