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belka [17]
3 years ago
10

Use the pythagorean theorem to find the value of a.​

Mathematics
2 answers:
satela [25.4K]3 years ago
4 0

Answer:

a = 5

Step-by-step explanation:

Using Pythagoras' theorem in the right triangle

a² + 12² = 13²

a² + 144 = 169 ( subtract 144 from both sides )

a² = 25 ( take the square root of both sides )

a = \sqrt{25} = 5

wel3 years ago
3 0

Answer:

pythagoras theorem formula

h^2=p^2+b^2

here hypotenuse is 13

you can take a as either perpendicular or base

lets take it base

h^2=p^2+b^2

(13)^2=(12)^2+(a)^2

169=144+a^2

169-144=a^2

25=a^2

\sqrt{25}=a

5=a

Step-by-step explanation:

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Answer:

D.Place the compass on a point on the original line.

Complete Question:

A.Create only one arc that intersects the original line.

B.Create two arcs that intersect the original line.

C.Place the compass on a point off the original line.

D.Place the compass on a point on the original line.

Step-by-step explanation:

* Lets revise the steps of constructing parallel lines and a perpendicular line through a point on the line

# Contracting parallel lines

- Given: Line AB and point P not on AB

1. Draw a slant line through point P and intersects AB at point C, this line is the transversal of the parallel lines

2. Place the pin of the compass at point C and draw an arc intersects AB at D and CP at E

3. Without changing the distance of the compass put the pin of the compass on point P and draw an arc intersects CP at point Q

4. Use the compass to measure the distance from D to E and place the pin of the compass at point Q and draw an arc intersects the arc from P to CP at point U

5. Join P and U by a line this line is parallel to AB

# Constructing a perpendicular line through a point on the line

- Given line AB and point P lies on it

1. Place your compass pin at P and draw an arc of any size below AB that crosses the line twice at points C and D

2. Stretch the compass to a larger distance

3. Place the compass pin on point C and draw a small arc above the line

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5. Using a straightedge, join P and E where PE is perpendicular to AB

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∵ In second construction we put the pin of the compass at point P which lies in the original line AB

∴ The common step is:  "Place the compass on a point on the original line"

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