Hello,
7) A∪C={1,2,3,4,5,7,9}
8) A∩B={2,4}
C'= complement of C ={2,4,6}
9) A∪B∩C'={1,2,3,4,6,8}∩{2,4,6}={2,4,6}
10) A∪(B∩C')={1,2,3,4}∩{2,4,6}={1,2,3,4,6}
Are you blind?
When you have an irregular figure, you can divide it so that it becomes multiple normal figures. You already did this in the picture, now you just have to find the area of each shape and then add them all together.
From bottom to top:
A=1/2 (b1+b2)h
A= 1/2 (4+2.24)(2)
A= 6.24
(you have two of these on either side)
A=bh
A=6(4)
A=24
A=1/2 bh
A= 1/2 (4)(4)
A=8
(NOTE: there is an error in your drawing. The height of the triangle cant be determined because the 10 value spans over the entire figure when the wings of the rocket are 4 units long and then the body is 6 units long, making it equal 10 already. I'm assuming that the 10 is supposed to go from the bottom of the rectangle to the top of the triangle)
Total figure= 6.24 + 6.24 + 24 + 8
total figure = 44.48
Answer: xy=11 in.; yz= 13 in.; xz=13in.
Step-by-step explanation:
i’m pretty sure that’s it
Answer: Option d.
Step-by-step explanation:
You can solve the problem shown above keeping on mind the facts shown below:
Observe that there is a point in the graph in which there is a jump or a discontinuity between both parts of the function.
The point mentioned is at x=5
By definition, this indicates that the function shown is not continuous at that point.
Therefore, you can conclude that the value in which the graph is discontinuous is the value of the option d: 5
The perimeter of the triangle is B) 27.4
Please let me know if you need an explanation.