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mestny [16]
3 years ago
13

48 cookies; 50% increase​

Mathematics
2 answers:
zavuch27 [327]3 years ago
8 0

Answer:

its 72.00

Step-by-step explanation:

48.00 increased by 50% is 72.00

The increase is 24.00

saul85 [17]3 years ago
4 0

Answer:

72

Step-by-step explanation:

48÷2= 24

48+24= 72

Hope this helps! :)

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If two-fifths of a certain number is subtracted from twice the number, the result is 4. PLS ANSWER​
atroni [7]

Answer:

4

Step-by-step explanation:

2x-2/5=4

2x= 4+(2/5)

2x= 4/5+20/5

x=(22/5)/2

x= 22/10 or 11/5

check:

2(11/5)-2/5=(22/5)-(2/5)

=20/5

=4

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3 years ago
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Irina18 [472]

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The primary colors of light are red, green, and blue. If you subtract these from white you get cyan, magenta, and yellow. Mixing the colors generates new colors as shown on the color wheel, or the circle on the right. Mixing these three primary colors generates black.Step-by-step explanation:

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4 years ago
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A statistics professor plans classes so carefully that the lengths of her classes are uniformly distributed between 50.0 and 60.
Artist 52 [7]

Answer: 0.0250

Step-by-step explanation:

Given : A statistics professor plans classes so carefully that the lengths of her classes are uniformly distributed between 50.0 and 60.0 minutes.

We know that the uniform distribution is also known as rectangular distribution.

Density function for uniform distribution :f(x)=\dfrac{1}{b-a}

=\dfrac{1}{60-50}=\dfrac{1}{10}

Now, the probability that a given class period runs between 51.25 and 51.5 minutes :-

\int^{51.5}_{51.25}f(x)\ d(x)\\\\ \int^{51.5}_{51.25}\dfrac{1}{10}\ dx\\\\=\dfrac{1}{10} [x]^{51.5}_{51.25}\\\\=\dfrac{1}{10}(51.5-51.25)=0.0250

Hence, the probability that a given class period runs between 51.25 and 51.5 minutes = 0.0250

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3 years ago
Sigma Notation: Need Help!!
kkurt [141]
3 x -2^(n-1)

To answer this question, first solve the equation 3 x -2^(n-1) for n=1, n=2,
n=3, n=4, and n=5.

Where n=1
3 x -2^(1-1)
3 x -2^0
3 x 1
n1 = 3


Where n=2
3 x -2^(2-1)
3 x -2^1
3 x -2
n2 = -6


Where n=3
3 x -2^(3-1)
3 x -2^2
3 x 4
n3 = 12


Where n=4
3 x -2^(4-1)
3 x -2^3
3 x -8
n4 = -24


Where n=5
3 x -2^(5-1)
3 x -2^4
3 x 16
n5 = 48


The next step is to find the summation by adding n1 + n2 + n3 + n4 + n5.

3 + (-6) + (12) + (-24) + (48) =
3 - 6 + 12 - 24 + 48
= 33
The answer is C. 33
5 0
4 years ago
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