For this case we have the following equation:
h (t) = at ^ 2 + v * t + h0
Substituting values we have:
h (t) = - 16 * t ^ 2 + 60 * t + 3
We equate the equation to zero:
-16 * t ^ 2 + 60 * t + 3 = 0
We look for the roots of the polynomial:
t1 = -0.04935053979258153
t2 = 3.7993505397925817
We are left with the positive root and round:
t2 = 3.8 s
Answer:
t = 3.8 s
option 3
Area of the sector = 1/2 * r^2 * theta where theta is the angle subtended by the arc at the center ( in radians)
In this case m < theta = 360 - 235 = 125 degrees or 2.182 radians
So, the area of shaded area = 1/2 * 20^2 * 2.182 = 436.4 in^2
Answer:
2 is the required answer.
Step-by-step explanation:
<u>Solution:</u>
<u>Given</u><u>:</u>
-5x+3y=2..............(i)
Putting the value of y=2x in the equation (i); we get:
i.e -5x+3×2x=2
or, -5x+6x=2
or, x=2
i.e. x=2
y=2x=2×2=4
Answer: A
I'd have to say a because it's the closest answer or best estimate.
Answer:
336.8 cubic meter or 336.8m³
Step-by-step explanation:
In other to solve the above question we would be using the volume of a square based pyramid.
The formula for the volume of a square based pyramid is
1/3a²h
In the above question we are given the following values as:
Side length of the base = a = 11.1 m
Height of the pyramid = h = 8.2m
Volume of the square based pyramid = 1/3 × 11.1² × 8.2
= 336.774 cubic meter or 336.774 m³
Approximately to the nearest tenth = 336.8 cubic meter or 336.8m³
