Answer:
The mean is also increased by the constant k.
Step-by-step explanation:
Suppose that we have the set of N elements
{x₁, x₂, x₃, ..., xₙ}
The mean of this set is:
M = (x₁ + x₂ + x₃ + ... + xₙ)/N
Now if we increase each element of our set by a constant K, then our new set is:
{ (x₁ + k), (x₂ + k), ..., (xₙ + k)}
The mean of this set is:
M' = ( (x₁ + k) + (x₂ + k) + ... + (xₙ + k))/N
M' = (x₁ + x₂ + ... + xₙ + N*k)/N
We can rewrite this as:
M' = (x₁ + x₂ + ... + xₙ)/N + (k*N)/N
and (x₁ + x₂ + ... + xₙ)/N was the original mean, then:
M' = M + (k*N)/N
M' = M + k
Then if we increase all the elements by a constant k, the mean is also increased by the same constant k.
Answer:
<h2>17</h2>
Step-by-step explanation:
f(x) = 11 - 3x
f(-2) - <em>put x = -2 to the f(x):</em>
<em />
f(-2) = 11 - 3(-2) = 11 + 6 = 17
Answer:
Wish i can help but i don't understand that
Step-by-step explanation:
AB = ==> distance between the bottom of the plank; and the wall ===> 3 ft.
C ====> 49 degrees
For letter a, to solve for AC:
AC ==> HYPOTENUSE. The angle C is the OPPOSITE side of AB.
use sine :
sin A ===> opposite/hypotenuse
Solve:
sin 49 ====> 3/AC
AC ====> 3 / sin 49
AC ====> 3.96 ft.
For letter b, to solve for BC:
We are now given with the base (3 ft.); and; the hypotenuse (3.96 ft.) so we can use the Pythagorean theorem:
a^2 + b^2 = c^2
Let:
a ===> AB
b ===> BC
c ===> AC
(AB)^2 + (BC)^2 ===> (AC)^2
3^2 + (BC)^2 ===> (3.96)^2
(BC)^2 ===> (3.96)^2 - 3^2
(BC)^2 ===> 6.6816
sqrt (BC)^2 ===> sqrt 6.6816
Answer: BC ===> 2.58 ft.
Hope that helps!!!! : )
