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MArishka [77]
3 years ago
15

Kayla consumed 1800 calories on Monday. She consumed 500 more calories on Tuesday than she did on Monday. On Wednesday, she cons

umed 100 calories less than she had on Tuesday. Find the rate of change in calorie intake from Monday to Wednesday.
Mathematics
1 answer:
Mrrafil [7]3 years ago
6 0

Answer:  +200 calories/day

Step-by-step explanation:

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Sin 90 +cos 50 -tan1​
Feliz [49]

Answer:

1.62533254

Step-by-step explanation:

7 0
3 years ago
A rectangle has a length of
Marina CMI [18]

rectangle has a length of

18 feet. The width is x feet

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6 0
3 years ago
Suppose X, Y, and Z are random variables with the joint density function f(x, y, z) = Ce−(0.5x + 0.2y + 0.1z) if x ≥ 0, y ≥ 0, z
dexar [7]

Answer:

The value of the constant C is 0.01 .

Step-by-step explanation:

Given:

Suppose X, Y, and Z are random variables with the joint density function,

f(x,y,z) = \left \{ {{Ce^{-(0.5x + 0.2y + 0.1z)}; x,y,z\geq0  } \atop {0}; Otherwise} \right.

The value of constant C can be obtained as:

\int_x( {\int_y( {\int_z {f(x,y,z)} \, dz }) \, dy }) \, dx = 1

\int\limits^\infty_0 ({\int\limits^\infty_0 ({\int\limits^\infty_0 {Ce^{-(0.5x + 0.2y + 0.1z)} } \, dz }) \, dy } )\, dx = 1

C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y }(\int\limits^\infty_0 {e^{-0.1z} } \, dz  }) \, dy  }) \, dx = 1

C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0{e^{-0.2y}([\frac{-e^{-0.1z} }{0.1} ]\limits^\infty__0 }) \, dy  }) \, dx = 1

C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}([\frac{-e^{-0.1(\infty)} }{0.1}+\frac{e^{-0.1(0)} }{0.1} ])  } \, dy  }) \, dx = 1

C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}[0+\frac{1}{0.1}]  } \, dy  }) \, dx =1

10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2y} }{0.2}]^\infty__0  }) \, dx = 1

10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2(\infty)} }{0.2}+\frac{e^{-0.2(0)} }{0.2}]   } \, dx = 1

10C\int\limits^\infty_0 {e^{-0.5x}[0+\frac{1}{0.2}]  } \, dx = 1

50C([\frac{-e^{-0.5x} }{0.5}]^\infty__0}) = 1

50C[\frac{-e^{-0.5(\infty)} }{0.5} + \frac{-0.5(0)}{0.5}] =1

50C[0+\frac{1}{0.5} ] =1

100C = 1 ⇒ C = \frac{1}{100}

C = 0.01

3 0
3 years ago
The graph below is a portion of a complete graph. Which graph below is the complete graph assuming it is an even function
blondinia [14]
⭐Hola User_______________

⭐Here is your Answer. ...!!

_______________________

↪Actually welcome to the concept of the Graphs ..

↪Basically the given half graph is a parabolic graph of equation

↪y^2 = 4ax ...

↪thus the 3 graph option is the completion of the graph in the question ..

↪Option d.)

_________________________
7 0
3 years ago
Read 2 more answers
PLEASE HELP! ILL MARK BRAINLIEST
Lunna [17]

Subtracting a number from x shifts the graph that may places tot he right

Subtracting a number at the end of the equation, shifts the graph that many units down.

The answer would be: Shift the graph of y = x^2 right 2 units and then down 10 units.

4 0
3 years ago
Read 2 more answers
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