Answer:
the percent reduction is <u>33.6%</u> and the number of people who were issued a parking ticket are <u>42</u>.
Step-by-step explanation:
Given:
Last month in the village of 125 people were issued a parking ticket.
This month only 83 people were issued one.
Now, to find the percent reduction from this month to last month and the number of people who were issued a Parking ticket.
So, the reduction of the number of people who were issued a Parking ticket from this month to last month are:
125 people - 83 people = 42 people.
Thus, 42 people reduction from this month to last month.
Now, to get the percent reduction:
Therefore, the percent reduction is 33.6% and the number of people who were issued a parking ticket are 42.
Answer:
use logarithms
Step-by-step explanation:
Taking the logarithm of an expression with a variable in the exponent makes the exponent become a coefficient of the logarithm of the base.
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You will note that this approach works well enough for ...
a^(x+3) = b^(x-6) . . . . . . . . . . . variables in the exponents
(x+3)log(a) = (x-6)log(b) . . . . . a linear equation after taking logs
but doesn't do anything to help you solve ...
x +3 = b^(x -6)
There is no algebraic way to solve equations that are a mix of polynomial and exponential functions.
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Some functions have been defined to help in certain situations. For example, the "product log" function (or its inverse) can be used to solve a certain class of equations with variables in the exponent. However, these functions and their use are not normally studied in algebra courses.
In any event, I find a graphing calculator to be an extremely useful tool for solving exponential equations.
Answer:
1. coefficient
2. variable
3. constant
Step-by-step explanation:
9514 1404 393
Answer:
x= 10, corresponding
Step-by-step explanation:
Corresponding angles are in the same direction from their respective intersections. Here, the angles are both northwest of the point where the lines cross. The angles are corresponding.
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Corresponding angles are congruent, so we have ...
10x +10 = 110
10x = 100 . . . . . subtract 10
x = 10 . . . . . . . . divide by 10
