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Lunna [17]
3 years ago
7

What is the minimum value for the function y=2x^2-32x+256

Mathematics
1 answer:
sweet [91]3 years ago
3 0
The answer would be: 128

You can find minimum value by looking at the vertex. First, differentiate the equation and find the value of x.

<span> y=2x^2-32x+256
4x - 32=0
4x=32
x=8

If you put x=8, the value would be:
</span>y=2x^2-32x+256
y=2(8)^2-32(8)+256
y= 128- 256 + 256= 128
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Answer:

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Step-by-step explanation:

<u>Total number of students:</u>

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B.

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C.

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D.

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2 years ago
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Patrick has a $1000 bond with a 6% coupon. Howmuch interest will Patrick receive for this bond every 6 months?
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Total distance travelled = (x.a + 2x -10) miles .

How to solve such time related questions?

The key concept for solving such questions is the relationship between speed, distance and time.

The relationship between them is Distance = Speed X Time

The whole trip can be divided into two parts

Part 1 :- Speed = x mph  and time =  a hours

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Part 2 :- Speed = x -5mph  and time =  2 hours

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Total distance = (x.a + 2x -10) miles

Learn more about Distances here :

brainly.com/question/6716662

#SPJ4

4 0
2 years ago
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