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grin007 [14]
3 years ago
5

Look at the function below. f(x)=−x2−2x+8

Mathematics
1 answer:
enyata [817]3 years ago
7 0

Answer:

f(x) = -1(x+1)² + 9

Step-by-step explanation:

f(x) = -x² - 2x + 8

This is a down-opening parabola. Put the equation into vertex form. The y-coordinate of the vertex is the maximum.

factor out the leading coefficient

f(x) = -1(x²+2x) + 8

Complete the square

 coefficient of x term: 2

 divide in half: 1

 square it: 1²

 use 1² to complete the square:

f(x) = -1(x²+2x+1²) + 1² + 8

f(x) = -1(x+1)² + 9

vertex (-1,9)

maximum value of f(x) = 9

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c

Step-by-step explanation:

Since both equations express y in terms of x we can equate the right sides

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3 years ago
What is the value of x in this simplified expression
arsen [322]

Answer:

7

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8 0
3 years ago
Suppose that X is a subset of Y. Let p be the proposition ‘x is an element ofX’ and let q be the proposition ‘x is an element of
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Answer:

See answer below

Step-by-step explanation:

The statement ‘x is an element of Y \X’ means, by definition of set difference, that "x is and element of Y and x is not an element of X", WIth the propositions given, we can rewrite this as "p∧¬q". Let us prove the identities given using the definitions of intersection, union, difference and complement. We will prove them by showing that the sets in both sides of the equation have the same elements.

i) x∈AnB  if and only (if and only if means that both implications hold) x∈A and x∈B if and only if x∈A and x∉B^c (because B^c is the set of all elements that do not belong to X) if and only if x∈A\B^c. Then, if x∈AnB  then x∈A\B^c, and if x∈A\B^c then x∈AnB. Thus both sets are equal.

ii) (I will abbreviate "if and only if" as "iff")

x∈A∪(B\A) iff x∈A or x∈B\A iff x∈A or x∈B and x∉A iff x∈A or x∈B (this is because if x∈B and x∈A then x∈A, so no elements are lost when we forget about the condition x∉A) iff x∈A∪B.

iii) x∈A\(B U C) iff x∈A and x∉B∪C iff x∈A and x∉B and x∉C (if x∈B or x∈C then x∈B∪C thus we cannot have any of those two options). iff x∈A and x∉B and x∈A and x∉C iff x∈(A\B) and x∈(A\B) iff x∈ (A\B) n (A\C).

iv) x∈A\(B ∩ C) iff x∈A and x∉B∩C iff x∈A and x∉B or x∉C (if x∈B and x∈C then x∈B∩C thus one of these two must be false) iff x∈A and x∉B or x∈A and x∉C iff x∈(A\B) or x∈(A\B) iff x∈ (A\B) ∪ (A\C).

8 0
3 years ago
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9966 [12]

Answer:

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Step-by-step explanation:

Let n represent the number of nickels. Since Seth has 8 more nickels than dimes, then (n-8) is the number dimes.

Nickel is worth 5 cents and dime is worth 10 cents.  Thus, n nickels are worth 5n cents and (n-8) dimes are worth 10(n-8) cents. The total value of Seth's coins is $2.35 that is 235 cents, then

5n+10(n-8)=235.

Solve this equation:

5n+10n-80=235,\\ \\15n=235+80,\\ \\15n=315,\\ \\n=21.

6 0
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