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vodka [1.7K]
3 years ago
5

Which of the following correctly shows the Pythagorean theorem?

Mathematics
2 answers:
Ugo [173]3 years ago
7 0

Answer:

a²+b²=c²

Step-by-step explanation:

that is the formula for calculating pythagoras

ryzh [129]3 years ago
5 0
The pythagorean theorem is
a^2 + b^2 = c^2
which is D
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You can make 8 pints of purple paint by mixing 6 parts of blue paint to 2 parts of red paint. The employees in the paint departm
natta225 [31]

Answer & Step-by-step explanation:

Since we use 5 parts blue and 3 parts red, the total sections is 8.

28/8 = 3.5

We want to find the red which is 3 parts.

3.5 * 3 = 10.5.

Your answer should be 10.5 pints of red.

Hope this helps!

8 0
3 years ago
Multiply.
Nady [450]

\boxed{3\sqrt{22}\sqrt{58}\sqrt{18}=18\sqrt{638}}

<h2>Explanation:</h2>

Here we have the following expression:

3\sqrt{22}\sqrt{58}\sqrt{18}

So we need to simplify that radical expression. By property of radicals we know that:

\sqrt[n]{a}\sqrt[n]{b}=\sqrt[n]{ab}

So:

3\sqrt{22}\sqrt{58}\sqrt{18}=3\sqrt{22\times 58 \times 18}=3\sqrt{22968}

The prime factorization of 22968 is:

22968=2^3\cdot 3^2\cdot11\cdot 29

Hence:

3\sqrt{22968}=3\sqrt{2^3\cdot 3^2\cdot11\cdot 29}=3\sqrt{2^2\cdot 3^2\cdot 2\cdot 11\cdot 29}

By property:

\sqrt[n]{a^n}=a

So:

3\sqrt{2^2\cdot 3^2\cdot 2\cdot 11\cdot 29} \\ \\ 3(2)(3)\sqrt{2\cdot 11\cdot 29}=18\sqrt{638}

Finally:

\boxed{3\sqrt{22}\sqrt{58}\sqrt{18}=18\sqrt{638}}

<h2>Learn more:</h2>

Radical expressions: brainly.com/question/13452541

#LearnWithBrainly

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3 years ago
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Digiron [165]

/Answer:

4

Step-by-step explanation:

24 / 6 = 4

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3 years ago
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